2

下面的实现是稳定的，因为它使用<=而不是<在标记为 XXX 的行。这也使它更有效率。有没有理由使用<而不是<=在这条线上？

/**
class for In place MergeSort
**/
class MergeSortAlgorithm extends SortAlgorithm {
    void sort(int a[], int lo0, int hi0) throws Exception {
    int lo = lo0;
    int hi = hi0;
    pause(lo, hi);
    if (lo >= hi) {
        return;
    }
    int mid = (lo + hi) / 2;

        /*
         *  Partition the list into two lists and sort them recursively
         */
        sort(a, lo, mid);
        sort(a, mid + 1, hi);

        /*
         *  Merge the two sorted lists
         */
    int end_lo = mid;
        int start_hi = mid + 1;
    while ((lo <= end_lo) && (start_hi <= hi)) {
            pause(lo);
        if (stopRequested) {
                return;
            }
            if (a[lo] <= a[start_hi]) {                   // LINE XXX
                lo++;
            } else {
                /*  
                 *  a[lo] >= a[start_hi]
                 *  The next element comes from the second list, 
                 *  move the a[start_hi] element into the next 
                 *  position and shuffle all the other elements up.
                 */
        int T = a[start_hi];
                for (int k = start_hi - 1; k >= lo; k--) {
                    a[k+1] = a[k];
                    pause(lo);
                }
                a[lo] = T;
                lo++;
                end_lo++;
                start_hi++;
            }
        }
    }

    void sort(int a[])  throws Exception {
    sort(a, 0, a.length-1);
    }
}
4

2 回答 2

7

因为<=您的代码中的 确保不会交换相同值的元素（在排序数组的左半部分和右半部分）。而且，它避免了无用的交换。

if (a[lo] <= a[start_hi]) {
 /* The left value is smaller than or equal to the right one, leave them as is. */
 /* Especially, if the values are same, they won't be exchanged. */
 lo++;
} else {
 /*
  * If the value in right-half is greater than that in left-half,
  * insert the right one into just before the left one, i.e., they're exchanged.
  */
 ...
}

假设两半中的相同值元素（例如，'5'）和上面的运算符是<。如上面的注释所示，右边的 '5' 将被插入到左边的 '5' 之前，换句话说，相同值的元素将被交换。这意味着排序不稳定。而且，交换相同价值的元素效率低下。

我猜效率低下的原因来自算法本身。您的合并阶段是使用插入排序实现的（如您所知，它是 O(n^2)）。

当您对巨大的数组进行排序时，您可能需要重新实现。

于 2009-12-21T14:50:32.433 回答
2

Fastest known in place stable sort:
http://thomas.baudel.name/Visualisation/VisuTri/inplacestablesort.html

于 2011-03-14T11:13:33.733 回答