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我是 XML 新手，我似乎无法理解这个简单的问题......我正在检索一个带有节点 ID、品牌和型号的表......代码工作正常......但在表之间头部和身体，它还检索节点“john doe”。我猜 XPath 表达式有问题。

XML:

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="lab1.xsl"?>
<labs xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="lab.xsd">
   <lab name="FOA2A">
      <responsible>
         <name>John</name>
         <surname>Doe</surname>
      </responsible>
      <computers>
         <computer>
            <id>C001</id>
            <cpu>
               <make>Intel</make>
               <model>Core2duo</model>
               <clockspeed>2.4</clockspeed>
            </cpu>
            <monitor>
               <type>LCD</type>
               <size>17"</size>
            </monitor>
         </computer>
         <computer>
            <id>C002</id>
            <cpu>
               <make>AMD</make>
               <model>Quad</model>
               <clockspeed>3.0</clockspeed>
            </cpu>
            <monitor>
               <type>Plasma</type>
               <size>23"</size>
            </monitor>
         </computer>
         <computer>
            <id>C003</id>
            <cpu>
               <make>AMD</make>
               <model>DoubleQuad</model>
               <clockspeed>4.0</clockspeed>
            </cpu>
            <monitor>
               <type>LED</type>
               <size>32"</size>
            </monitor>
         </computer>
      </computers>
   </lab>
</labs>

XSLT：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
   <xsl:template match="/">
      <html>
         <head>TEST</head>
         <body>
            <table border="1">
               <thead>
                  <tr>
                     <td>Computer ID</td>
                     <td>CPU</td>
                     <td>Monitor</td>
                  </tr>
               </thead>
               <tbody>
                  <xsl:apply-templates />
               </tbody>
            </table>
         </body>
      </html>
   </xsl:template>
   <xsl:template match="labs/lab/computers">
      <xsl:for-each select="computer">
         <tr>
            <td>
               <xsl:value-of select="id/text()" />
            </td>
            <td>
               <xsl:value-of select="cpu/make/text()" />
            </td>
            <td>
               <xsl:value-of select="cpu/model/text()" />
            </td>
         </tr>
      </xsl:for-each>
   </xsl:template>
</xsl:stylesheet>
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1 回答 1

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只需将第二个所有模板移至 apply-templates 并进行如下更改：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
   <xsl:template match="/">
      <html>
         <head>TEST</head>
         <body>
            <table border="1">
               <thead>
                  <tr>
                     <td>Computer ID</td>
                     <td>CPU</td>
                     <td>Monitor</td>
                  </tr>
               </thead>
               <tbody>
                  <xsl:for-each select="labs/lab/computers/computer">
                     <tr>
                        <td>
                           <xsl:value-of select="id/text()" />
                        </td>
                        <td>
                           <xsl:value-of select="cpu/make/text()" />
                        </td>
                        <td>
                           <xsl:value-of select="cpu/model/text()" />
                        </td>
                     </tr>
                  </xsl:for-each>
               </tbody>
            </table>
         </body>
      </html>
   </xsl:template>
</xsl:stylesheet>

或另一种解决方案将选择添加到应用模板：

 <xsl:apply-templates select="labs/lab/computers"/>
于 2013-10-12T13:37:57.370 回答