language-agnostic - What is the name of this common algorithm?

Question

Here's the problem - I think it's a very common one with a well documented answer, but I'm not sure what the name of it is to find the answer:

I have a number n(260) between 0 and x(359).

I want to add a value of 100 to n but instead of the result being 360 I want it to cycle back round to 0

It works the other way as well e.g. n minus 270 should equal 349

Any ideas if the algorithm has a name?

Answer 1

模运算是解决这个问题的正确方法......

Answer 2

这是一个模组功能。如果你取 260 mod 360 之类的东西，答案将是 260。如果你取 360 mod 360，你得到 0。它相当于欧几里得除法的余数。

Answer 3

我想，您是在询问 modul_to 操作或除法提醒。

n_new = (n_old + 100) % (x + 1)
n_new = (260 + 100) % 360

UPD：值（n_old，n_new）需要定义为“unsigned int”，以便始终获得积极的提醒。