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我正在使用以下 LOJ 查询，它使用 CTE 来生成日期范围：

Declare @inquiryStartDate DateTime;
Declare @inquiryEndDate DateTime;
Declare @inquiryMortgageNumber nvarchar(50);

SET @inquiryStartDate = '2013-07-01';
SET @inquiryEndDate = '2013-07-31';
SET @inquiryMortgageNumber = '12345678';

With DateRange As (
    SELECT ID, Date
    FROM     d_Dates
    WHERE  (Date BETWEEN @inquiryStartDate AND @inquiryEndDate)
)
Select DateRange.ID, DateRange.Date,f_MortgageSnapshots.MortgageNumber, f_MortgageSnapshots.Investor_ID
From DateRange
LEFT OUTER JOIN f_MortgageSnapshots On DateRange.ID = f_MortgageSnapshots.SnapshotDate_ID
WHERE f_MortgageSnapshots.MortgageNumber = @inquiryMortgageNumber;

我得到了这个：

在此处输入图像描述

但我想要这个：

在此处输入图像描述

我究竟做错了什么？

快速说明，f_MortgageSnapshots 表中只有 2 行用于抵押贷款 12345678。

在此处输入图像描述

解决方案在这里！

声明@inquiryStartDate 日期时间；声明@inquiryEndDate 日期时间；声明@inquiryMortgageNumber nvarchar(50);

SET @inquiryStartDate = '2013-07-01'; SET @inquiryEndDate = '2013-07-31'; SET @inquiryMortgageNumber = '7078575';

With DateRange As (
SELECT ID, d_Dates.Date
FROM     d_Dates
WHERE  (d_Dates.Date BETWEEN @inquiryStartDate AND @inquiryEndDate)
 )
Select DateRange.ID, DateRange.Date,f_MortgageSnapshots.MortgageNumber, f_MortgageSnapshots.Investor_ID
From DateRange Left Join f_MortgageSnapshots 
     On DateRange.ID = f_MortgageSnapshots.SnapshotDate_ID
        And  MortgageNumber = @inquiryMortgageNumber;
4

2 回答 2

2

试试这个：

With DateRange As (
SELECT ID, Date
FROM     d_Dates
WHERE  (Date BETWEEN @inquiryStartDate AND @inquiryEndDate)
 )
   Select d.ID, d.Date, s.MortgageNumber, s.Investor_ID
   From DateRange d
      Left Join f_MortgageSnapshots s
         On d.ID = s.SnapshotDate_ID
            And  MortgageNumber = @inquiryMortgageNumber;

此外，在使用 CTE 时，您真的不需要点击日期表

With DateRange As (
SELECT ID, inquiryStartDate ADate
Union All
Select ID + 1, ADate + 1
FROM DateRange 
Where ADate < @inquiryEndDate)
Select d.ID, d.Date, s.MortgageNumber, s.Investor_ID
From DateRange d
    Left Join f_MortgageSnapshots s
        On d.ID = s.SnapshotDate_ID
           And  MortgageNumber = @inquiryMortgageNumber
OPTION (MAXRECURSION 2000);

MortgageNumber如果您希望空行显示and的一些默认值，请Investor_ID使用以下Coalesce() 函数：

With DateRange As (
SELECT ID, inquiryStartDate ADate
Union All
Select ID + 1, ADate + 1
FROM DateRange 
Where ADate < @inquiryEndDate)
Select d.ID, d.Date, 
   Coalesce(s.MortgageNumber, 'DefaultMortgageNumber') MortgageNumber,
   Coalesce(s.Investor_ID , -1) Investor_ID
From DateRange d
    Left Join f_MortgageSnapshots s
        On d.ID = s.SnapshotDate_ID
           And  MortgageNumber = @inquiryMortgageNumber
OPTION (MAXRECURSION 2000);
于 2013-10-11T21:02:41.790 回答
1

我认为 MortgageNumber 过滤器实际上是来自 f_MortgageSnapshots 的过滤器。既然你有一个左连接，我会做这样的事情：

Declare @inquiryStartDate DateTime;
Declare @inquiryEndDate DateTime;
Declare @inquiryMortgageNumber nvarchar(50);

SET @inquiryStartDate = '2013-07-01';
SET @inquiryEndDate = '2013-07-31';
SET @inquiryMortgageNumber = '12345678';

With DateRange As (
    SELECT ID, Date
    FROM     d_Dates
    WHERE  (Date BETWEEN @inquiryStartDate AND @inquiryEndDate)
)
Select DateRange.ID, DateRange.Date,f_MortgageSnapshots.MortgageNumber, 
       f_MortgageSnapshots.Investor_ID
From DateRange
LEFT OUTER JOIN f_MortgageSnapshots On DateRange.ID 
     = f_MortgageSnapshots.SnapshotDate_ID and MortgageNumber = @inquiryMortgageNumber;
于 2013-10-11T21:06:04.787 回答