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让我们有以下类:

class Functor{
    int even;
    int odd;
    Functor(int even, int odd){
        this->even=even;
        this->odd=odd;
    }
    void operator()(int x){
         if (x%2==0) even+=x;
         else odd+=x;
    }
}
int _tmain(int argc, _TCHAR* argv[])
{
    Functor* e= new Functor(0,0);//Now we have pointer to instance of Functor
    return 0;
}

问题: 让我们有指向函数foo和 Functor 实例的指针e,这样in(*foo)定义的函数和函数具有相同的签名。如果不明确重写?operator()Functorfoovoid (*e)(int x)void (*e)(int x)

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