0

I am trying to print a Fibonacci sequence using a do-while loop in java and can't understand this. Needs to be between 0 and 100.

I have the following code:

int prevPrevVal = 0;
int prevVal = 1;
int currVal;
System.out.println(prevPrevVal);
System.out.println(prevVal);

do
{       
    currVal = prevVal + prevPrevVal;
    System.out.println(currVal);

    prevPrevVal = prevVal;
    prevVal = currVal;          
} while (prevVal <= 100);
4

6 回答 6

3

这是一个简化的程序,通过在 while 循环中提供条件限制来找出斐波那契数列。希望大家对此有所了解......!

    int a=0;
    int b=0;
    int temp=1;
    do {    
        a=b;
        b=temp;
        temp=a+b;
        System.out.println(temp);
    }while(temp<100);
于 2018-07-09T10:47:01.443 回答
1

设法用两个变量来做到这一点,并且没有打印超出范围的数字。对不起,如果它很糟糕,这是我编程的第一天:)

    int x = 0;
    int y = 1;

    do
    {
        System.out.println(x);
        y = x + y;
        if (y < 100)
        {
            System.out.println(y);
        }
        x = x + y;
    } while (x < 100);
于 2020-04-28T19:22:51.580 回答
0

使用文档do-while中循环的基本结构:

do {
    statement(s)
} while (expression);

您在“语句”部分中想要的是通过每次迭代增加(并可能输出)您的结果。使用循环的基本斐波那契数do-while列如下所示:

int prevVal = 1;
int prevPrevVal = 0;
int currVal;
do {
    // Add the two numbers
    currVal = prevVal + prevPrevVal;
    // "Bump" up prevPrevVal to prevVal, and prevVal to currVal
    prevPrevVal = prevVal;
    prevVal = currVal;
    // Output to the screen
    System.out.println(currval + "\n");
} while(expression);
于 2013-10-11T05:32:49.213 回答
0

这应该是你的解决方案

public static void main(String[] args) {

     int prevVal = 1;
     int prevPrevVal = 0;
     int n = 0;
     do{
         int currVal = prevVal + prevPrevVal;
         prevPrevVal = prevVal;
         prevVal = currVal;
         System.out.print(currVal+" ");
         n++;
     }while(n<5);//n is the number of terms


}
于 2013-10-11T05:27:32.360 回答
0

干得好 :

int prevVal = 1;
int prevPrevVal = 0;
        do{
        int currVal = prevVal + prevPrevVal;
                    //currVal is your Fibonacc seq.
        prevPrevVal = prevVal;
        prevVal = currVal;
    }
    while(yourCondition);
于 2013-10-11T05:27:56.990 回答
0

由于您希望斐波那契的条款高达 100,只需更改while (prevVal <= 100);while (prevVal+prevPrevVal <= 100);

这将打印多达 89 个。

于 2015-07-03T14:06:21.133 回答