c# - C# 切换和计数子串匹配

Question

尝试通过记录类型（即行的第一个字符）来计算文件中特定行的出现次数。我的总行数是正确的，我的“其他”计数是正确的，但我的切换结果并没有计算总行数。foreach 运行了 13 次，但计数没有更新。

static void Main(string[] args)
{
int i1LineCount = 0;
int i2LineCount = 0;
int i3LineCount = 0;
int i4LineCount = 0;
int iOther = 0;
int iCount = File.ReadLines(@"c:\single.txt").Count();

foreach (string line in File.ReadLines(@"c:\single.txt"))
{
String sFirstChar = line.Substring(0, 1);
switch (sFirstChar)
{
    case "1":
    i1LineCount = i1LineCount+1;
    break;
    case "2":
    i2LineCount = i2LineCount+1;
    break;
    case "3":
    i3LineCount = i3LineCount+1;
    break;
    case "4":
    i4LineCount = i4LineCount+1;
    break;
    default:
    iOther = iOther+1;
    break;
}
}
Console.WriteLine("Line Count = " + iCount);
Console.WriteLine("1 lines = " + i1LineCount);
Console.WriteLine("2 lines = " + i1LineCount);
Console.WriteLine("3 lines = " + i1LineCount);
Console.WriteLine("4 lines = " + i1LineCount);
Console.WriteLine("Other lines = " + iOther);
}

我正在阅读的 txt 文件看起来像（没有 # 前面的 '，没有它我无法让它显示出来）：

'#  
\  
1  
4  
4  
2  
2  
2  
3  
2  
4  
4  
'#

我得到的结果是：

Line Count = 13  
1 lines = 1  
2 lines = 1  
3 lines = 1  
4 lines = 1  
Other lines = 3  

我应该得到：

Line Count = 13  
1 lines = 1  
2 lines = 4  
3 lines = 1  
4 lines = 4  
Other lines = 3  

Answer 1

你写了i1LineCount4次。

代码应该是：

Console.WriteLine("Line Count = " + iCount);
Console.WriteLine("1 lines = " + i1LineCount);
Console.WriteLine("2 lines = " + i2LineCount);
Console.WriteLine("3 lines = " + i3LineCount);
Console.WriteLine("4 lines = " + i4LineCount);
Console.WriteLine("Other lines = " + iOther);

Answer 2

1您每次都打印出行数：

Console.WriteLine("Line Count = " + iCount);
Console.WriteLine("1 lines = " + i1LineCount);
Console.WriteLine("2 lines = " + i1LineCount);
Console.WriteLine("3 lines = " + i1LineCount);
Console.WriteLine("4 lines = " + i1LineCount);
Console.WriteLine("Other lines = " + iOther);

您需要打印出 i2、i3、i4 等。

Answer 3

检查您的 Console.WriteLines...

Console.WriteLine("Line Count = " + iCount);
Console.WriteLine("1 lines = " + i1LineCount);
Console.WriteLine("2 lines = " + i1LineCount);
Console.WriteLine("3 lines = " + i1LineCount);
Console.WriteLine("4 lines = " + i1LineCount);
Console.WriteLine("Other lines = " + iOther);

应该...

Console.WriteLine("Line Count = " + iCount);
Console.WriteLine("1 lines = " + i1LineCount);
Console.WriteLine("2 lines = " + i2LineCount);
Console.WriteLine("3 lines = " + i3LineCount);
Console.WriteLine("4 lines = " + i4LineCount);
Console.WriteLine("Other lines = " + iOther);

Answer 4

你一直在打印i1LineCount你可能需要这个：

Console.WriteLine("Line Count = " + iCount);
Console.WriteLine("1 lines = " + i1LineCount);
Console.WriteLine("2 lines = " + i2LineCount);
Console.WriteLine("3 lines = " + i3LineCount);
Console.WriteLine("4 lines = " + i4LineCount);
Console.WriteLine("Other lines = " + iOther);

我也建议使用数组。