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我正在使用 spring 3.0 和 mongoDB 创建一个示例 Web 应用程序。以下是我的 root-context.xml 文件。

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

    <!-- Root Context: defines shared resources visible to all other web components -->
    <import resource="classpath:mongo-config.xml"/>

</beans>

我的 mongo-config.xml 文件是

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" 
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xmlns:p="http://www.springframework.org/schema/p" 
        xmlns:c="http://www.springframework.org/schema/c"
        xmlns:tx="http://www.springframework.org/schema/tx"
        xmlns:context="http://www.springframework.org/schema/context"
        xmlns:mongo="http://www.springframework.org/schema/data/mongo"
        xmlns:util="http://www.springframework.org/schema/util"
        xsi:schemaLocation="
            http://www.springframework.org/schema/beans 
            http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
            http://www.springframework.org/schema/tx 
            http://www.springframework.org/schema/tx/spring-tx-3.1.xsd
            http://www.springframework.org/schema/context
            http://www.springframework.org/schema/context/spring-context-3.1.xsd
            http://www.springframework.org/schema/data/mongo
            http://www.springframework.org/schema/data/mongo/spring-mongo-1.0.xsd
            http://www.springframework.org/schema/util 
            http://www.springframework.org/schema/util/spring-util-3.1.xsd">

    <!-- Default bean name is 'mongo'. write concern set to SAFE to ensure unique indexes -->
    <mongo:mongo host="localhost" port="27017" write-concern="SAFE"/>

    <mongo:repositories base-package="com.dashboard.repositories" />

    <bean id="mongoDbFactory" class="org.springframework.data.mongodb.core.SimpleMongoDbFactory">
        <constructor-arg name="mongo" ref="mongo"/>
        <constructor-arg name="databaseName" value="DASHBOARD"/>
        <constructor-arg name="credentials" ref="userCredentials"/>
    </bean>

    <bean id="mongoTemplate" class="org.springframework.data.mongodb.core.MongoTemplate">
        <constructor-arg name="mongoDbFactory" ref="mongoDbFactory"/>
        <property name="writeResultChecking">
            <util:constant static-field="org.springframework.data.mongodb.core.WriteResultChecking.EXCEPTION" ></util:constant>
        </property>
    </bean>

    <bean id="userCredentials" class="org.springframework.data.authentication.UserCredentials">
        <constructor-arg name="username" value="test"/>
        <constructor-arg name="password" value="abc123"/>
    </bean>

</beans>

当我启动 tomcat 服务器时，没有创建数据库“仪表板”。这段代码有什么问题，请帮助我。提前致谢。

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1 回答 1

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为了使它对其他观众可见，我会将我的评论放入答案中。在 Mongo 中，模式是动态的和异构的，因此 mongo 在插入任何数据之前无法创建固定模式作为 RDMS。这里有更详细的解释。

于 2013-10-10T17:08:39.700 回答