1

我有一个 HTML 表单：

<form action="something.php" method="POST" enctype="multipart/form-data" id="color">
<fieldset>
    <legend><h2><span style="color: #993300; text-shadow: #808080 2px 1px 2px; font-size: 25px;">Color Preferences:</span></h2></legend>&nbsp;
    <p><table>
        <tbody>
            <tr>
                <td width="350px;"><span style="color: #993300;">*</span> Colors you consider to use to your new Site:</td>
                <td>
                                  <br/> 
                                  <input type="checkbox" name="color[]" value="Black" /> Black<br/> 
                                  <input type="checkbox" name="color[]" value="Blue" /> Blue<br/> 
                                  <input type="checkbox" name="color[]" value="Brown" /> Brown<br/> 
                                  <input type="checkbox" name="color[]" value="Gray" /> Gray<br/> 
                                  <input type="checkbox" name="color[]" value="Green" /> Green<br/> 
                </td>
            </tr>
        </tbody>
    </table></p>
</fieldset>
<input type="submit" name="submit" value="Submit" /> <input type="reset" name="reset" value="Reset" />

为了执行颜色表单，我使用了一个 PHP 作为：

$color = $_POST['color'];    
if (!isset($color))
       {
        unset($_GET['do']);
         $message = "Error = Colors are required. Please try again.";
         break;
         } else {
         $N = count($color);
         for($i=0; $i < $N; $i++){
         echo($color[$i] . " ");
         }
       }

但是当我在输出区域测试我的代码时，它只给出一个“数组”作为结果。你能帮我修复这个代码吗？（我需要将选定的颜色作为输出而不是“Array”。）

我什至将我的代码更改为：

$color = $_POST['color'] && $_POST['color'] = array ('Black','Blue','Brown','Gray','Green','Orange','Pink','Purple','Red','Silver','Tan','White','Yellow','Dark','Light');
            if (!isset($_POST['color'])) 
            {
                unset($_GET['do']);
                echo "Error = Colors are required. Please try again.";
            } else {
                $n = count($_POST['color']);
                echo("You selected $n color(s): ");
                for($i=0; $i < $n; $i++)
                {
                    echo($_POST['color'][$i] . " ");
                }
            }

但结果仍然只是“数组”而不是颜色名称。你能帮我解决这个问题吗？

我什至将我的代码更改为：

$color = $_POST['color'] && $_POST['color'] = array ('Black','Blue','Brown','Gray','Green','Orange','Pink','Purple','Red','Silver','Tan','White','Yellow','Dark','Light');
            if (!isset($_POST['color'])) 
            {
                unset($_GET['do']);
                echo "Error = Colors are required. Please try again.";
            } else {
                $n = count($_POST['color']);
                echo("You selected $n color(s): ");
                for($i=0; $i < $n; $i++)
                {
                    echo($_POST['color'][$i] . " ");
                }
            }

但结果仍然只是“数组”而不是颜色名称。你能帮我解决这个问题吗？

4

2 回答 2

0

尝试这个：

PHP代码：

if (isset($_POST['submit'])) {

        if (!isset($_POST['color'])) {
            unset($_GET['do']);
            echo "Error = Colors are required. Please try again.";
        } else {
            $color = $_POST['color'];
            $N = count($color);
            for ($i = 0; $i < $N; $i++) {
                echo($color[$i] . " ");
            }
        }
    }
于 2013-10-10T13:35:32.180 回答
0

使用 color[]，您将收到一个数组 ($_POST['color'])。您可以测试它是 isset() 还是 empty()

如果它不为空，那么您可以迭代这些值，例如：

$n = count($_POST['color']);
echo("You selected $n color(s): ");
for($i=0; $i < $n; $i++)
{
  echo($_POST['color'][$i] . " ");
}

（未经测试。代码取自这里：http ://www.html-form-guide.com/php-form/php-form-checkbox.html ）

于 2013-10-10T13:30:35.410 回答