php - 如何将这 3 个查询组合成一个 MySQL 查询？

Question

以下每个查询都为我提供了我想要的结果，但我想将它们组合成一个查询。

我想输出 3 列：$row->day, $row->otherPageCount, $row->indexCount

有一张表tracking包含所有数据。

1）。

SELECT COUNT(`page`) AS indexCount FROM `tracking`
WHERE `page` = 'index.php'
AND `date`
BETWEEN DATE_ADD(NOW(),INTERVAL -30 DAY)
AND NOW()
GROUP BY DATE(`date`)

2）。

SELECT COUNT(`page`) AS otherPageCount FROM `tracking`
WHERE `page` != 'index.php'
AND `date`
BETWEEN DATE_ADD(NOW(),INTERVAL -30 DAY)
AND NOW()
GROUP BY DATE(`date`)

3）。

SELECT DATE(`date`) AS day FROM `tracking`
WHERE `date`
BETWEEN DATE_ADD(NOW(),INTERVAL -30 DAY)
AND NOW()
GROUP BY DATE(`date`)

Answer 1

SELECT DATE(`date`),
       COUNT(`page`) AS indexCount, 
       SUM(`page` = 'index.php') as idx_count, 
       SUM(`page` <> 'index.php') as not_idx_count
FROM `tracking`
WHERE `date` BETWEEN DATE_ADD(NOW(),INTERVAL -30 DAY) AND NOW()
GROUP BY DATE(`date`)

Answer 2

您可以为此使用 IF：

SELECT DATE(`date`), 
  SUM( IF( `page` = 'index.php', 1, 0 ) ) indexCount, 
  SUM( IF( `page` != 'index.php', 1, 0 ) ) otherPageCount
FROM `tracking`
WHERE `date` BETWEEN DATE_ADD(NOW(),INTERVAL -30 DAY) AND NOW()
GROUP BY DATE(`date`)

于尔根的回答做同样的事情，但使 IF 隐含。如果您了解它的工作原理，那将是更好的答案。