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我将一系列文本输入到我的 sip 解析器中。第一个花费的时间最长，不管哪个是第一个。我想知道 spirit::lex 进行第一次解析时是否有任何初始化工作？

template <typename Lexer>
struct sip_token : lex::lexer<Lexer>
{
    sip_token()
    {
        this->self.add_pattern
            ("KSIP", "sip:")
            ("KSIPS", "sips:")
            ("USERINFO", "[0-9a-zA-Z-_.!~*'()]+(:[0-9a-zA-Z-_.!~*'()&=+$,]*)?@")
            ("DOMAINLBL", "([0-9a-zA-Z]|([0-9a-zA-Z][0-9a-zA-Z-]*[0-9a-zA-Z]))")
            ("TOPLBL", "[a-zA-Z]|([a-zA-Z][0-9a-zA-Z-]*[0-9a-zA-Z-])")
            ("INVITE", "INVITE")
            ("ACK", "ACK")
            ("OPTIONS", "OPTIONS")
            ("BYE", "BYE")
            ("CANCEL", "CANCEL")
            ("REGISTER", "REGISTER")
            ("METHOD", "({INVITE}|{ACK}|{OPTIONS}|{BYE}|{CANCEL}|{REGISTER})")
            ("SIPVERSION", "SIP\\/[0-9]\\.[0-9]")
            ("PROTOCOAL", "SIP\\/[^/]+\\/UDP")
            ("IPV4ADDR", "(\\d{1,3}\\.){3}\\d{1,3}")                
            ("HOSTNAME", "[^ \t\r\n]+")            
            ("SIPURL", "{KSIP}{USERINFO}?{HOSTNAME}(:[0-9]+)?")
            ("SIPSURL", "{KSIPS}{USERINFO}?{HOSTNAME}(:[0-9]+)?")
            ("SENTBY", "({HOSTNAME}|{IPV4ADDR})(:[0-9]+)?")
            ("GENPARM", "[^ ;\\n]+=[^ ;\r\\n]+")
            ("TOKEN", "[0-9a-zA-Z-.!%*_+~`']+")
            ("NAMEADDR", "({TOKEN} )?<({SIPURL}|{SIPSURL})>")
            ("STATUSCODE", "\\d{3}")
            ("REASONPHRASE", "[0-9a-zA-Z-_.!~*'()&=+$,]*")
            ("CR", "\\r")
            ("LF", "\\n")
        ;

        this->self.add
            ("{METHOD} {SIPURL} {SIPVERSION}", T_REQ_LINE)
            ("{SIPVERSION} {STATUSCODE} {REASONPHRASE}", T_STAT_LINE)
            ("{CR}?{LF}", T_CRLF)
            ("Via: {PROTOCOAL} {SENTBY}(;{GENPARM})*", T_VIA)
            ("To: {NAMEADDR}(;{GENPARM})*", T_TO)
            ("From: {NAMEADDR}(;{GENPARM})*", T_FROM)
            ("[0-9a-zA-Z -_.!~*'()&=+$,;/?:@]+", T_OTHER)

        ;
    }
};

语法：

template <typename Iterator>
struct sip_grammar : qi::grammar<Iterator>
{
  template <typename TokenDef>
  sip_grammar(TokenDef const& tok)
    : sip_grammar::base_type(start)     
  {
    using boost::phoenix::ref;
    using boost::phoenix::size;
    using boost::spirit::qi::eol;

    start = request  | response;
    response = stat_line >> *(msg_header) >> qi::token(T_CRLF);
    request = req_line >> *(msg_header) >> qi::token(T_CRLF);
    stat_line = qi::token(T_STAT_LINE) >> qi::token(T_CRLF);
    req_line = qi::token(T_REQ_LINE) >> qi::token(T_CRLF);
    msg_header = (qi::token(T_VIA) | qi::token(T_TO) | qi::token(T_FROM) | qi::token(T_OTHER))
      >> qi::token(T_CRLF);    
  }

  std::size_t c, w, l;
  qi::rule<Iterator> start, response, request, stat_line, req_line, msg_header; 
};

定时：

gettimeofday(&t1, NULL);
bool r = lex::tokenize_and_parse(first, last, siplexer, g);
gettimeofday(&t2, NULL);

结果：

pkt1 time=40945(us)
pkt2 time=140
pkt3 time=60
pkt4 time=74
pkt5 time=58
pkt6 time=51
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1 回答 1

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显然，它确实:)

Lex 可能会生成一个 DFA（可能为每个 Lexer 状态生成一个 DFA）。这很可能是最耗时的事情。使用探查器确定：/

现在你可以

这意味着您将编写一个“额外”main来将 DFA 生成为 C++ 代码：

#include <boost/spirit/include/lex_lexertl.hpp>
#include <boost/spirit/include/lex_generate_static_lexertl.hpp>

#include <fstream>

#include "sip_token.hpp"

using namespace boost::spirit;

int main(int argc, char* argv[])
{
    // create the lexer object instance needed to invoke the generator
    sip_token<lex::lexertl::lexer<> > my_lexer; // the token definition

    std::ofstream out(argc < 2 ? "sip_token_static.hpp" : argv[1]);

    // invoke the generator, passing the token definition, the output stream 
    // and the name suffix of the tables and functions to be generated
    //
    // The suffix "sip" used below results in a type lexertl::static_::lexer_sip
    // to be generated, which needs to be passed as a template parameter to the 
    // lexertl::static_lexer template (see word_count_static.cpp).
    return lex::lexertl::generate_static_dfa(my_lexer, out, "sip") ? 0 : -1;
}

生成的代码示例如下（在教程中的字数示例中）： http: //www.boost.org/doc/libs/1_54_0/libs/spirit/example/lex/static_lexer/word_count_static.hpp

于 2013-10-10T08:42:07.460 回答