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我使用冒泡排序方法按顺序（从最小到最大）对输入数字进行排序，并且我有它自己的方法。然后，在下一个方法中（我需要按顺序排列数字）似乎忽略了我已经在前一个方法中对数字进行了排序。我没有正确调用方法还是什么？谢谢！

import java.util.Scanner;
public class hw6 {
public static int getOrder(int n1, int n2, int n3, int n4, int n5) {
    Scanner in = new Scanner(System.in);

    if (n1>n2){
        int t = n1;
        n1 = n2;
        n2 =t;
    }
    if (n2>n3){
        int t = n2;
        n2 = n3;
        n3 =t;
    }
    if (n3>n4){
        int t = n3;
        n3 = n4;
        n4 =t;
    }
    if (n4>n5){
        int t = n4;
        n4 = n5;
        n5 =t;
    }
    if (n1>n2){
        int t = n1;
        n1 = n2;
        n2 =t;
    }
    if (n2>n3){
        int t = n2;
        n2 = n3;
        n3 =t;
    }
    if (n3>n4){
        int t = n3;
        n3 = n4;
        n4 =t;
    }
    if (n1>n2){
        int t = n1;
        n1 = n2;
        n2 =t;
    }
    if (n2>n3){
        int t = n2;
        n2 = n3;
        n3 =t;
    }
    if (n1>n2){
        int t = n1;
        n1 = n2;
        n2 =t;
    }
    System.out.println(n1+" "+n2+" "+n3+" "+n4+" "+n5);

    return n1+n2+n3+n4+n5;//cards now in order from least to greatest
 }
 public static int getRank(int n1, int n2, int n3, int n4, int n5) {
 int order;
 int rank = 1;
 order = getOrder(n1, n2, n3, n4, n5);

 if (n1 == n2 && n1 == n3 && n1 == n4 || 
     n2 == n3 && n2 == n4 && n2 == n5)
     System.out.println("Four of a kind");
 else if (n1 == n2 && n1 == n3 && n4 == n5 ||
          n1 == n2 && n3 == n4 && n3 == n5)
     System.out.println("Full house");
 else if (n2 == n1+1 && n3 == n2+1 && n4 == n3+1 && n5 == n4+1)
     System.out.println("Straight");
 else if (n1 == n2 && n1 == n3 || n2 == n3 && n2 == n4 ||
          n3 == n4 && n3 == n5)
     System.out.println("Three of a kind");
 else
     System.out.println("A high card");

 return rank;
 }       
 public static void main(String[] args) {
    Scanner in = new Scanner(System.in);
    int n1, n2, n3, n4, n5; //input 
    int order;
    int rank;

    System.out.print("Enter  (1-13):");
    n1 = in.nextInt();
    System.out.print("Enter  (1-13):");
    n2 = in.nextInt();
    System.out.print("Enter  (1-13):");
    n3 = in.nextInt();
    System.out.print("Enter  (1-13):");
    n4 = in.nextInt();
    System.out.print("Enter  (1-13):");
    n5 = in.nextInt();

    order = getOrder(n1, n2, n3, n4, n5);
    rank = getRank(n1, n2, n3, n4, n5);
}

}

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1 回答 1

2

Java 是按值传递的，因此该getOrder方法接收值的副本。本地副本已更改，但原始变量 frommain未更改。

为了使更改持续存在，我将创建一个数组或一个ArrayList来包含这些值。然后将其传递给您的方法以更改这些值。该方法将接收对数组或对象的引用的副本ArrayList，因此更改将保留在对象中。

于 2013-10-09T22:53:56.260 回答