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我正在开发一个 Android 应用程序。我需要比较位置并查看它们之间的距离。但是，我有很多。我发现最简单的方法是将它们存储在字符串数组中，然后进行比较。我已经搜索过了，但我还没有找到一种方法将字符串数组中的项目变成一个位置。我试过：

double distance

Location locationA = new Location(“point A”)

locationA.setLatitude(latitude);

locationA.setLongitude(Longitude);

Location locationB = new Location(“point B”);

locationB.setLatitude(Latitude.get(0));

LocationB.setLongitude(latitude.get(0));

distance = locationA.distanceTo(locationB);

但它不起作用。我的代码发布在下面：

NearestStations.java

public class Neareststations extends Activity implements LocationListener {
LocationManager mLocationManager;
@SuppressLint("NewApi")
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.neareststations);
    // Show the Up button in the action bar.
    getActionBar().setDisplayHomeAsUpEnabled(true);



        mLocationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);

        Location location = mLocationManager.getLastKnownLocation(LocationManager.GPS_PROVIDER);
        double longitude = location.getLongitude();
        double latitude = location.getLatitude();
        Log.i("MYTAG", String.valueOf(longitude));
        Log.i("MYTAG", String.valueOf(latitude));
        if(location != null && location.getTime() > Calendar.getInstance().getTimeInMillis() - 2 * 60 * 1000) {
            // Do something with the recent location if it is less than two minutes old
            Log.i("MYTAG", String.valueOf(location));
            Log.i("MYTAG", String.valueOf(longitude));
            Log.i("MYTAG", String.valueOf(latitude));
        }
        else {
            mLocationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER, 5, 50, this);
            Log.i("MYTAG", String.valueOf(location));
        }
    }

    public void onLocationChanged(Location location) {
        if (location != null) {
        // Do something withthe current location
            Log.i("MYTAG", String.valueOf(location));

        }
    }

    public void onProviderDisabled(String arg0) {}
    public void onProviderEnabled(String arg0) {}
    public void onStatusChanged(String arg0, int arg1, Bundle arg2) {}

    String[] Stations = getResources().getStringArray(R.array.Stations);
    String[] Longitude = getResources().getStringArray(R.array.Longitude);
    String[] Latitude = getResources().getStringArray(R.array.Latitude);

    Map<String, String> myMap = new HashMap<String, String>();{
    for (int i = 0; i <8; i++) {
        myMap.put(Stations[i], Latitude[i]);
    }
    }

    Map<String, String> myMap1 = new HashMap<String, String>();{
    for (int h = 0; h <8; h++) {
        myMap1.put(Stations[h], Longitude[h]);
    }
    }

我怎样才能做到这一点？我的字符串数组是标准的，并且有诸如

<item>-87.669147</item>
<item>-87.680622</item>

感谢您的帮助。

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2 回答 2

5

字符串需要转换为双精度。此外，您应该在比较两点时使用 distanceBetween()，但 distanceTo() 将适用于较小的距离。

这是一个将字符串值转换为双精度值以与 Location 一起使用的基本示例。距离将以米为单位返回，因此如果您想要英里，请乘以 0.000621371192237334。

double distance;  

String str_lat_start = "29.287260";
String str_lon_start = "-81.100327";
String str_lat_end = "26.016045";
String str_lon_end = "-80.150169";

double lat_start = 0;
double lon_start = 0;
double lat_end = 0;
double lon_end = 0;

try {

    lat_start = Double.parseDouble( str_lat_start ); 
    lon_start = Double.parseDouble( str_lon_start );
    lat_end = Double.parseDouble( str_lat_end );
    lon_end = Double.parseDouble( str_lon_end );

} catch (NumberFormatException e) {
    Log.v("Main", "Convert to Double Failed : ");
}

Location locationA = new Location("point A");  
locationA.setLatitude( lat_start );  
locationA.setLongitude( lon_start );  

Location locationB = new Location("point B");  
locationB.setLatitude( lat_end );  
locationB.setLongitude( lon_end );  

distance = locationA.distanceTo(locationB) * 0.000621371192237334;
于 2013-10-09T21:49:37.523 回答
1 
float[] results = new float[3];
    Location.distanceBetween(locationA.getLatitude(), locationA.getLongitude(), locationB.getLatitude(), locationB.getLongitude(), results);

A 和 B 之间的距离为results[0]。

于 2013-10-09T22:00:32.233 回答