0

我有 2 张桌子

domain_info 和 tb2

我的表格运行良好并将数据输入数据库

这是我页面的顶部

  <?php
$action = isset($_POST['action']) ? $_POST['action'] : "";

if($action=='create'){
//include database connection
include 'db_connect.php';

//write query
$query = "insert into domains_info 
set
domain = '".$mysqli->real_escape_string($_POST['domain'])."', 
domain_account = '".$mysqli->real_escape_string($_POST['domain_account'])."',
renew_date  = '".$mysqli->real_escape_string($_POST['renew_date'])."'";

if( $mysqli->query($query) ) {
//if saving success
header("Location:domains.php");
}else{
echo "Database Error: Unable to create record.";
}
$mysqli->close();
}

这是表格

<select id="domain_account" name="domain_account" class="txtBox">
<option value="">-select-</option>
<option value="a">a</option>
<option value="b">b</option>
<option value="c">c</option>                 
</select>

我尝试并像这样更改了我的页面顶部

<?php
$action = isset($_POST['action']) ? $_POST['action'] : "";

if($action=='create'){
//include database connection
include 'db_connect.php';

//write query
$query = "insert into domains_info 
set
domain = '".$mysqli->real_escape_string($_POST['domain'])."', 
domain_account = '".$mysqli->real_escape_string($_POST['domain_account'])."',
renew_date  = '".$mysqli->real_escape_string($_POST['renew_date'])."'";

if( $mysqli->query($query) ) {
//if saving success
header("Location:domains.php");
}else{
echo "Database Error: Unable to create record.";
}
$mysqli->close();
}

$query = "select id, data 
                        from tb2
                        where id='".$mysqli->real_escape_string($_REQUEST['id'])."'
                        limit 0,1";

$result = $mysqli->query( $query );
$row = $result->fetch_assoc();

$id = $row['id'];
$data = $row['data'];

并更新了我的表格

<select id="domain_account" name="domain_account" class="txtBox">
<option value="">-select-</option>
<option value="<?php echo$data; ?>"><?php echo$data; ?></option>    
</select>

正如你所知道的，我对此很陌生，而且它不起作用。

抱歉，我没有解释我想要实现的目标，我正在尝试显示一个包含数据库数据的下拉表单。

4

1 回答 1

2

尝试使用数据库填充下拉列表：

<?php
$query = "select id, data from tb2";
$result = $mysqli->query( $query );

echo '<select id="domain_account" name="domain_account" class="txtBox">';
echo '<option value="">-select-</option>';
while ($row = $result->fetch_assoc()){
?>
    <option value="<?php echo $row['data']; ?>"><?php echo $row['data']; ?></option>
<?php    
}
echo "</select>";
?>
于 2013-10-09T21:28:56.283 回答