2

我有麻烦了！

我正在动态地生成很多网格视图，并为列提供动态值。列是一样的。

我想知道如何设置此列的大小。

那是我的代码，我的努力。

    private void generateControls( List<List<DataRow>> grids)
    {
        DataTable dt = new DataTable();

        int i = 0;
        foreach (List<DataRow> lst in grids)
        {
            dt = lst.CopyToDataTable();

            GridView grv = new GridView();
            grv.AlternatingRowStyle.BackColor = System.Drawing.Color.FromName("#cccccc");
            grv.HeaderStyle.BackColor = System.Drawing.Color.Gray;

            grv.Width = new Unit("100%");
            //grv.RowStyle.Wrap = false;
            grv.RowStyle.Width = new Unit("100%");

            grv.ID = "grid_view" + i;
            grv.DataSource = dt;
            grv.DataBind();

          /*  grv.Columns[0].ItemStyle.Width = new Unit("5%");
            grv.Columns[1].ItemStyle.Width = new Unit("7%");
            grv.Columns[2].ItemStyle.Width = new Unit("12%");
            grv.Columns[3].ItemStyle.Width = new Unit("12%");
            grv.Columns[4].ItemStyle.Width = new Unit("7%");
            grv.Columns[5].ItemStyle.Width = new Unit("7%");
            grv.Columns[6].ItemStyle.Width = new Unit("23%");
            grv.Columns[7].ItemStyle.Width = new Unit("22%");
            grv.Columns[8].ItemStyle.Width = new Unit("5%");*/

            Label lblBlankLines = new Label();
            lblBlankLines.Text = "<br />";

            Panel panelGrid = new Panel();
            panelGrid.ID = "panel_grid" + i;


            Label lblTipo = new Label();
            string tipoOcorrencia = lst[0]["Ocorrência"].ToString();

           /* 
            * Capitalized
            * TextInfo myTI = new CultureInfo("pt-BR", false).TextInfo;

            string novoTipoOcorrencia = myTI.ToTitleCase(tipoOcorrencia);*/

            int quantidade = lst.Count;
            lblTipo.Text = " - " + tipoOcorrencia + ": " + quantidade;


            LinkButton lkBtn = new LinkButton();
            lkBtn.ID = "link_button" + i;
            lkBtn.Text = "Exibir | Ocultar";
            lkBtn.Attributes["onClick"] = "javascript:return ocultaGrid('" + panelGrid.ID + "'), false";

            panel_status.Controls.Add(lblBlankLines);
            panel_status.Controls.Add(lkBtn);
            panel_status.Controls.Add(lblTipo);


            panelGrid.Controls.Add(grv);

            panel_status.Controls.Add(panelGrid);

            panel_status.DataBind();

            i++;
        }
    }

我试图获取列，但出现错误，告诉我索引访问无效。我如何访问该网格视图中的列？

4

1 回答 1

5

使用 RowDataBound 事件处理程序：

计算您的索引并确保您也没有尝试访问不存在的列。

示例见链接：

http://msdn.microsoft.com/en-us/library/ms178296(v=vs.100).ASPX

grv.RowDataBound += grv_RowDataBound;

    private void grv_RowDataBound(object sender, GridViewRowEventArgs e)
    {

        if (e.Row.RowType == DataControlRowType.Header)
        {

                   e.Row.Cells[0].Width = new Unit("5%");
                   e.Row.Cells[1].Width = new Unit("7%");
                   e.Row.Cells[2].Width = new Unit("12%");
                   e.Row.Cells[3].Width = new Unit("12%");
                   e.Row.Cells[4].Width = new Unit("7%");
                   e.Row.Cells[5].Width = new Unit("7%");
                   e.Row.Cells[6].Width = new Unit("23%");
                   e.Row.Cells[7].Width = new Unit("22%");
                   e.Row.Cells[8].Width = new Unit("5%"); 
        }

    }
于 2013-10-09T13:26:36.727 回答