php - 如何使用2个表将php连接到navicat

Question

$i = 1;
$sql = "
    SELECT
        heroes.char_id, characters.char_name, heroes.class_id, heroes.count, 
        heroes.played, heroes.active FROM heroes, characters
    WHERE characters.obj_Id = heroes.char_id AND heroes.played = 1
    ";
$query = mysql_query($sql);
while($row = mysql_fetch_array($query))
{
    echo "
    <tr>
    <td><span id='lefttop'><b><font color='#007aa2'>".$i++."&nbsp;</font></td><td><b><font color='#f6ff00'>".$row['char_name']."</font></td></span><div style='float:right;'><td><b>&nbsp;".$row['count']."</td></div> <br />
    </tr>
    ";
}

echo "";
?>

任何人都可以帮忙吗？我试图在java服务器上制作一个英雄状态脚本，我需要连接到2个表，分别是“英雄”（这是我得到英雄的地方）和“角色”（这是我得到英雄名字的地方）

Answer 1

试试这个寺庙：

<?php
$sql1 = "SELECT * your table1";
$query1 = mysql_query($sql);
while($row1 = mysql_fetch_array($query1))
{
echo "<tr>";
    $sql2 = "SELECT * your table2";
    $query2 = mysql_query($sql2);
    while($row2 = mysql_fetch_array($query2))
    {

        echo "<td>[yor Vars here]</td>";
    }
echo "</tr>";
}

?>