python - 将输入的整数分离到一个列表中，检查列表中的每个元素是否满足要求

Question

input_list = input("Enter numbers separated by spaces: ")

number = input_list.split()
for n in number:
     a = int(n)
if len(number)!=5 or number>5 or number<0 :
        print ('invalid input')
        if 0< a <=5:
            print ('x'* a)
        elif a == 0:
            print ('.')

我的程序正在检查输入的 5 位数字，就好像它们是一个数字一样，但我希望我的程序首先确保输入了 5 位数字，然后检查它们是否在 0 和 5 之间，但是程序将所有 5 位数字组合成一个数字，我希望程序自己检查列表的每个元素，然后在打印任何内容之前，我希望程序检查输入的数字是否满足所有条件，如果不打印（无效输入）并停止它们

Answer 1

input_list = input("Enter numbers separated by spaces: ")

numbers = input_list.split()

if len(numbers) == 5 and all(0 <= int(n) <= 5 for n in numbers):
    print("ok")
    print("".join(numbers))
else:
    print("invalid")

Answer 2

我在 python 2 中使用 raw_input。对于 python 3，输入很好。

input_list = raw_input("Enter numbers separated by spaces: ").split()
numbers = [int(n) for n in input_list if 0 <= int(n) <= 5]
if len(numbers) != 5:
    print ('invalid input')

for a in numbers:
    if a == 0:
        print ('.')
    else:
        print ('x'* a)

Answer 3

input_list = input("Enter numbers separated by spaces: ")

number = input_list.split()
if len(number) == 5:
    for n in number:
        a = int(n)
        if 0< a <=5:
            print ('x'* a)
        elif a == 0:
            print ('.')
        else:
            print ("Number does not lie in the range 0 to 5.")
else:
    print ("Invalid Input.")
Yes, the above works but is should check input first to make sure it is valid

Answer 4

number = raw_input("Enter numbers separated by spaces: ")
2   num_list = number.split()
3   for n in num_list:
4       a = 'True'
5       if int(n) <0 or int(n) >5:
6           a = 'False'
7           break       
8   if (len(num_list) == 5) and a == 'True':
9       for n in num_list:
10          b = int(n)
11          if 0< b <=5:
12              print ('x'* b)
13          elif b == 0:
14              print ('.')
15  else:
16      print 'Invalid Input!'