我在 CMD 中创建了一个运行命令的进程。
var process = Process.Start("CMD.exe", "/c apktool d app.apk");
process.WaitForExit();
如何在不显示实际 CMD 窗口的情况下运行此命令?
我在 CMD 中创建了一个运行命令的进程。
var process = Process.Start("CMD.exe", "/c apktool d app.apk");
process.WaitForExit();
如何在不显示实际 CMD 窗口的情况下运行此命令?
您可以使用 WindowsStyle-Propertyindicate whether the process is started in a window that is maximized, minimized, normal (neither maximized nor minimized), or not visible
process.StartInfo.WindowStyle = ProcessWindowStyle.Hidden
并将您的代码更改为此,因为您在初始化对象时启动了该过程,因此将无法识别属性(在启动该过程后设置的属性)。
Process proc = new Process();
proc.StartInfo.FileName = "CMD.exe";
proc.StartInfo.Arguments = "/c apktool d app.apk";
proc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
proc.Start();
proc.WaitForExit();
There are several issues with your program, as pointed out in the various comments and answers. I tried to address all of them here.
ProcessStartInfo psi = new ProcessStartInfo();
psi.FileName = "apktool";
//join the arguments with a space, this allows you to set "app.apk" to a variable
psi.Arguments = String.Join(" ", "d", "app.apk");
//leave it to the application, not the OS to launch the file
psi.UseShellExecute = false;
//choose to not create a window
psi.CreateNoWindow = true;
//set the window's style to 'hidden'
psi.WindowStyle = ProcessWindowStyle.Hidden;
var proc = new Process();
proc.StartInfo = psi;
proc.Start();
proc.WaitForExit();
The main issues:
cmd /c
when not necessary尝试这个 :
proc.StartInfo.CreateNoWindow = true;
proc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
proc.WaitForExit();
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.CreateNoWindow = true;
startInfo.UseShellExecute = false;
startInfo.FileName = "dcm2jpg.exe";
startInfo.WindowStyle = ProcessWindowStyle.Hidden;
startInfo.Arguments = "-f j -o \"" + ex1 + "\" -z 1.0 -s y " + ex2;