我的公钥在一个名为 publickey.key 的文件中,该文件的内容是这样的,
MIIBIjANBgkqhkiG9w0BAQEFAAOCAQ8AMIIBCgKCAQEAtixUGzGpLXgZ7AV1HfmIHV/FEF+fww77FekRc2oLhUOd4HitwCPo76fjtdsQBEt8w9HZ3CXVphaAU2BA6MEZJ3ShVMsdAXb2ZA1C+lu7k1GV9M/BhucTg35HujSK647Sc5MwVLwFsN80dAnGsZF8gwb2TNUzXHwzbAb30T01zuqf8RCM75OwKZFYqzu7FOVrtk/w9mh92MOXG0l7WSqNIctu8Kxka/tEJJIA5nqMGNMocjwprXy66NS7FFy1GY+NnxfFLtODqq0tllc50UCDsnqSvNmj2wcnAcsCzNOoxPPgp7t8S+sQvOzgc5W3CDjIsYEiGD+vzSVNkGiRou577wIDAQAB
/////// 在我的 .php 文件中,我按照以下步骤使用此公钥加密我的字符串
$fp=fopen ("publickey.key","r");
$publicKey=fread($fp,8192);
fclose($fp);
$encrypted = '';
$secret='what i want to encrypt';
if (!openssl_public_encrypt($secret, $encrypted, $publicKey))
{
die('Failed to encrypt data');
}
但我收到了这个错误。
警告:openssl_public_encrypt() [function.openssl-public-encrypt]: key parameter is not a valid public key in......
我的代码中有什么做错了吗?请帮忙!