I have an array like this :
var array = [1,20,50,60,78,90];
var id = 50;
How can i remove the id from the array and return a new array that does not have the value of the id in new array?
I have an array like this :
var array = [1,20,50,60,78,90];
var id = 50;
How can i remove the id from the array and return a new array that does not have the value of the id in new array?
对于复杂的解决方案,您可以使用 method _.reject()
,以便您可以将自定义逻辑放入回调:
var removeValue = function(array, id) {
return _.reject(array, function(item) {
return item === id; // or some complex logic
});
};
var array = [1, 20, 50, 60, 78, 90];
var id = 50;
console.log(removeValue(array, id));
对于简单的情况,使用更方便的方法_.without()
:
var array = [1, 20, 50, 60, 78, 90];
var id = 50;
console.log(_.without(array, id));
var array = [1,20,50,60,78,90];
var id = 50;
var result = _.filter(array, function(x) { return x != id });
您可以使用splice,尽管它不是下划线的 API:
arrayObject.splice(index,howmany,item1,.....,itemX)
在您的示例中:
var index = _.indexOf(array, id);
array.splice(index, 1);