javascript - Removing Item from array with Underscore.js

Question

I have an array like this :

var array = [1,20,50,60,78,90];
var id = 50;

How can i remove the id from the array and return a new array that does not have the value of the id in new array?

Answer 1

对于复杂的解决方案，您可以使用 method _.reject()，以便您可以将自定义逻辑放入回调：

var removeValue = function(array, id) {
    return _.reject(array, function(item) {
        return item === id; // or some complex logic
    });
};
var array = [1, 20, 50, 60, 78, 90];
var id = 50;
console.log(removeValue(array, id));

对于简单的情况，使用更方便的方法_.without()：

var array = [1, 20, 50, 60, 78, 90];
var id = 50;
console.log(_.without(array, id));

演示

Answer 2

_filter也可以。这与_reject相反。

var array = [1,20,50,60,78,90];
var id = 50;

var result = _.filter(array, function(x) { return x != id });

http://jsfiddle.net/kman007_us/WzaJz/5/

Answer 3

您可以使用splice，尽管它不是下划线的 API：

arrayObject.splice(index,howmany,item1,.....,itemX)

在您的示例中：

var index = _.indexOf(array, id);
array.splice(index, 1);