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我试图让我的程序打印字母而不是数字。我曾经char c = static_cast<char>(N);尝试这样做,但它不起作用,而是打印不是 (az) 的字符图像 我怎样才能将数字打印为字母?

#include  <cstdlib>
#include  <iostream>
using namespace std;

// Function getUserInput obtains an integer input value from the user.
//  This function performs no error checking of user input.
int getUserInput()
{
    int N(0);

    cout << endl << "Please enter a positive, odd integer value, between (1-51): ";
    cin >> N;
    if (N < 1 || N > 51 || N % 2 == 0)
    {
        cout << "Error value is invalid!" << "\n";
        cout << endl << "Please enter a positive, odd integer value, between (1-51): ";
        cin >> N;
        system("cls");
    }

    cout << endl;
    return N;
} // end getUserInput function

//  Function printDiamond prints a diamond comprised of N rows of asterisks.
//  This function assumes that N is a positive, odd integer.
void printHourglass(int N)
{
    char c = static_cast<char>(N);
    for (int row = (N / 2); row >= 1; row--)
    {
        for (int spaceCount = 1; spaceCount <= (N / 2 + 1 - row); spaceCount++)
            cout << ' ';
        for (int column = 1; column <= (2 * row - 1); column++)
            cout << c;
        cout << endl;
    } // end for loop
    // print top ~half of the diamond ...
    for (int row = 1; row <= (N / 2 + 1); row++)
    {
        for (int spaceCount = 1; spaceCount <= (N / 2 + 1 - row); spaceCount++)
            cout << ' ';
        for (int column = 1; column <= (2 * row - 1); column++)
            cout << c;
        cout << endl;
    } // end for loop

    // print bottom ~half of the diamond ...


    return;
} // end printDiamond function

int main()
{
    int N = 1;

    while (N == 1)
    {
        printHourglass(getUserInput());
        cout << endl;
        cout << "Would you like to print another hourglass? ( 1 = Yes, 0 = No ):";
        cin >> N;
    }
} // end main function
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2 回答 2

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  1. C函数,itoa
  2. C++,使用字符串流
  3. boost::lexical_cast

实际上,对于您的情况,您可以直接打印出来。cout << N

于 2013-10-08T00:37:15.810 回答
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这些字母没有以A开头1或类似的东西编号。您可能使用的是 ASCII/UTF-8 系统。因此,在 中printHourglass,替换cout << N

cout << static_cast<char>('A' + count - 1);
于 2013-10-08T02:24:27.880 回答