1

我正在尝试加入这 4 个表:

顾客:

  • id_customer;
  • 姓名;

雇主:

  • id_employer;
  • id_customer;

products_to_employer

  • id_product;
  • id_employer;

产品

  • id_product;
  • 名称_产品;
  • 代码;
  • 价格;

我基本上试图获得客户的所有产品。基本上每个产品都与一个 id_employer 相关,但每个雇主都与一个客户相关,所以我想要的是带来所有与雇主无关但与他的“父母”客户无关的产品。

我想要得到的结果是:

结果:

示例:变量 $id_customer:4

产品结果:

  • id_customer (id nr 4)
  • 名称_产品;
  • 名称_产品;
  • 代码;
  • 价格;
4

2 回答 2

1

这是要求:

我基本上试图获得客户的所有产品

因此,只需where为过滤器应用一些连接和子句id_customer

select p.* from products p
join products_to_employer pe on p.id_product = pe.id_product
join employers e on pe.id_employer = e.id_employer
join customers c on e.id_customer = c.id_customer
where c.id_customer = 4

注意:应该不需要添加id_customer到结果中,因为您已经在通过它进行过滤。

于 2013-10-07T22:23:56.003 回答
0
select c.id_customer, c.name, p.name_product, p.code, p.price
from products p
    inner join products_to_employer pte on (pte.id_product = p.id_product)
    inner join employers e on (e.id_employer = pte.id_employer)
    inner join customers c on (c.id_customer = e.id_customer)
where c.id_customer = 4
于 2013-10-07T22:23:47.977 回答