我正在尝试将文件 fmarom android 上传到 Web 服务器，在服务器端使用 aspx，我正在使用我在以下位置找到的示例代码：http: //www.codicode.com/art/upload_files_from_android_to_a_w.aspx 我的问题是我收到此错误消息：java.net.ProtocolException：方法不支持请求正文：POST。
现在我正在寻找这个错误消息，我发现我在服务器端有问题，我的问题的解决方案是通过像这样编辑 Web.config 在服务器上启用 HTTP GET 和 HTTP POST。
<configuration>
<system.web>
<webServices>
<protocols>
<add name="HttpGet"/>
<add name="HttpPost"/>
</protocols>
</webServices>
</system.web>
</configuration>
但在这一行仍然有相同的错误消息：
DataOutputStream dos = new DataOutputStream(conn.getOutputStream());
这是我的课程代码：
HttpFileUpload.java：
package com.batyalon.tizko;
import java.io.DataOutputStream;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import android.util.Log;
public class HttpFileUpload implements Runnable{
URL connectURL;
String responseString;
String Title;
String Description;
byte[ ] dataToServer;
FileInputStream fileInputStream = null;
HttpFileUpload(String urlString, String vTitle, String vDesc){
try{
connectURL = new URL(urlString);
Title= vTitle;
Description = vDesc;
}catch(Exception ex){
Log.i("HttpFileUpload","URL Malformatted");
}
}
void Send_Now(FileInputStream fStream){
fileInputStream = fStream;
Sending();
}
void Sending(){
String iFileName = "ovicam_temp_vid.mp4";
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
String Tag="fSnd";
try
{
Log.e(Tag,"Starting Http File Sending to URL");
// Open a HTTP connection to the URL
HttpURLConnection conn = (HttpURLConnection)connectURL.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
//The line which gives the error:
DataOutputStream dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"title\""+ lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(Title);
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"description\""+ lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(Description);
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + iFileName +"\"" + lineEnd);
dos.writeBytes(lineEnd);
Log.e(Tag,"Headers are written");
// create a buffer of maximum size
int bytesAvailable = fileInputStream.available();
int maxBufferSize = 1024;
int bufferSize = Math.min(bytesAvailable, maxBufferSize);
byte[ ] buffer = new byte[bufferSize];
// read file and write it into form...
int bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable,maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0,bufferSize);
}
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
fileInputStream.close();
dos.flush();
Log.e(Tag,"File Sent, Response: "+String.valueOf(conn.getResponseCode()));
InputStream is = conn.getInputStream();
// retrieve the response from server
int ch;
StringBuffer b =new StringBuffer();
while( ( ch = is.read() ) != -1 ){ b.append( (char)ch ); }
String s=b.toString();
Log.i("Response",s);
dos.close();
}
catch (MalformedURLException ex)
{
Log.e(Tag, "URL error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e(Tag, "IO error: " + ioe.getMessage(), ioe);
}
}
@Override
public void run() {
// TODO Auto-generated method stub
}
}
我的 MainActivity 代码：
try {
// Set your file path here
FileInputStream fstrm = new FileInputStream(Environment.getExternalStorageDirectory().toString()+ File.separator + "bina/shruttech/3_0.png");
// Set your server page url (and the file title/description)
HttpFileUpload hfu = new HttpFileUpload("http://XXXX:8080/fileup.aspx", "mytitle","mydescription");
hfu.Send_Now(fstrm);
} catch (FileNotFoundException e) {
// Error: File not found
}
我的 fileup.aspx 代码：
protected void Page_Init(object sender, EventArgs e)
{
string vTitle = "";
string vDesc = "";
string FilePath = Server.MapPath("/files/cur_file.mp4");
if (!string.IsNullOrEmpty(Request.Form["title"]))
{
vTitle = Request.Form["title"];
}
if (!string.IsNullOrEmpty(Request.Form["description"]))
{
vDesc = Request.Form["description"];
}
HttpFileCollection MyFileCollection = Request.Files;
if (MyFileCollection.Count > 0)
{
// Save the File
MyFileCollection[0].SaveAs(FilePath);
}
}
在此先感谢您的帮助...