2

I have a working fiddle, but the autocomplete does not display anything in the browser. The fiddle can be seen here: Working Fiddle

In the HTML, I have one input element for testing purposes:

<head>
<link rel="stylesheet" href="http://code.jquery.com/ui/1.10.3/themes/smoothness/jquery-ui.css" />
<link rel="stylesheet" href="http://code.jquery.com/mobile/1.3.2/jquery.mobile-1.3.2.min.css" />
<script src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
<script src="http://code.jquery.com/mobile/1.3.2/jquery.mobile-1.3.2.min.js"></script>
<script src="http://code.jquery.com/ui/1.10.3/jquery-ui.js"></script>

<script type ="text/javascript" src="myScripts.js"></script>
<script type ="text/javascript" src="jquery.csv-0.71.js"></script>
<script type ="text/javascript" src="csvToArray.v2.1.js"></script>
</head>


<body>
<div data-role="page" id="main">

    <div data-role="header">
        <h1>Test</h1>
    </div>

    <div id="contentDiv" data-role="content">   
        <input type="text" id="food" placeholder="Type (First Name) Here" />        
    </div>

</div>
</body>

In my javascript, I am initializing a json variable by reading text from a file. I have tested that my initialization is successful by displaying an alert of my json variable. I am trying to use that json variable as the source in my autocomplete. Below, I have simplified my javascript by hard coding the initialization of the json variable in order to narrow down the problem:

var jsonVersion =       
[{"description":"mac and cheese", "servingSize":"1 cup", "calories":"500"},
 {"description":"slice of pizza", "servingSize":"1 slice", "calories":"400"},
 {"description":"oreo cookie", "servingSize":"1 cookie", "calories":"100"},
 {"description":"salad", "servingSize":"1 cup", "calories":"50"},
 {"description":"apple", "servingSize":"1 apple", "calories":"70"}];

$('#food').autocomplete({
                     source: jsonVersion,
                     select: function (event, ui) {
                     selectedObj = ui.item;
                     alert("selected object=" + selectedObj.value);
                                                    },
                     minLength: 1
                        });

Any idea why this would work in the fiddle but not in the browser? I am not getting any browser errors. Simply nothing is being displayed when I type in the textbox.

EDIT

Perhaps it is in the way I am populating my jsonVersion - although when I print the jsonVersion via "alert", it looks right. Any advice on what I am doing wrong here would be appreciated. Here is the entire javascript file. "data" is an array of arrays and I am looping through each of those arrays to create an object, in turn creating an array of Objects. Then I convert the array of objects to json using stringify:

$(function ($) {
    var jsonVersion;
    var arrayOfObjects;
    $.ajax({
            type: "GET",
            url: "test.js",
            dataType: "text",
            success: function(data) {
                                    data = $.csv.toArrays(data);
                                    arrayOfObjects = new Array();
                                    for(var i=1; i<data.length; i++)//skipping over header
                                    {
                                        var foodObject = new Object();
                                        foodObject.label = data[i][1];
                                        foodObject.weight = data[i][2];
                                        foodObject.servingSize = data[i][3];
                                        foodObject.calories = data[i][4];
                                        arrayOfObjects.push(foodObject);
                                    }
                                    jsonVersion = JSON.stringify(arrayOfObjects);
                                    alert(jsonVersion); 
                                    }
            });

    $('#food').autocomplete({
                            source: jsonVersion,
                            select: function (event, ui) {
                            selectedObj = ui.item;
                            alert("selected object=" + selectedObj.value);
                                                            },
                            minLength: 1
                            });
})
4

2 回答 2

1

你有两个主要问题：

  1. 您正在将字符串传递给source自动完成选项。执行此操作时，小部件会尝试使用该字符串作为 URL 以从中检索结果。由于此字符串是您构建为 AJAX 调用结果的数组的 JSON 表示形式，因此这显然不会按您期望的方式工作。你应该简单地使用arrayOfObjects。

  2. 您正在successAJAX 请求的回调之外初始化自动完成小部件。这意味着自动完成小部件使用空源进行初始化。您可以通过简单地将初始化移动到success回调中来修复。

解决这两个问题应该可以解决您的问题：

$(function ($) {
    $.ajax({
        type: "GET",
        url: "test.js",
        dataType: "text",
        success: function(data) {
            data = $.csv.toArrays(data);
            var arrayOfObjects = [];
            for(var i=1; i<data.length; i++)//skipping over header
            {
                var foodObject = new Object();
                foodObject.label = data[i][1];
                foodObject.weight = data[i][2];
                foodObject.servingSize = data[i][3];
                foodObject.calories = data[i][4];
                arrayOfObjects.push(foodObject);
            }

            $('#food').autocomplete({
                source: arrayOfObjects,
                select: function (event, ui) {
                    selectedObj = ui.item;
                    alert("selected object=" + selectedObj.value);
                },
                minLength: 1
            });            
        }
    });
});
于 2013-10-07T17:33:05.700 回答
0

看起来您的脚本不在 dom 就绪处理程序中。

在jsfiddle中，在左侧面板的第二个下拉菜单中onload告诉应用程序为脚本添加一个包装 onload 处理程序 - 如果您选择on head它将无法工作

jQuery(function ($) {
    var jsonObject = [{
        "label": "mac and cheese",
            "servingSize": "1 cup",
            "calories": "500"
    }, {
        "label": "slice of pizza",
            "servingSize": "1 slice",
            "calories": "400"
    }, {
        "label": "oreo cookie",
            "servingSize": "1 cookie",
            "calories": "100"
    }, {
        "label": "salad",
            "servingSize": "1 cup",
            "calories": "50"
    }, {
        "label": "apple",
            "servingSize": "1 apple",
            "calories": "70"
    }];

    $('#food').autocomplete({
        source: jsonObject,
        select: function (event, ui) {
            selectedObj = ui.item;

            alert("selected object=" + selectedObj.value);
        },
        minLength: 1
    });
})

演示：小提琴

更新：

$(function ($) {
    var arrayOfObjects = [];
    $.ajax({
        type: "GET",
        url: "test.js",
        dataType: "text",
        success: function (data) {
            data = $.csv.toArrays(data);
            for (var i = 1; i < data.length; i++) //skipping over header
            {
                var foodObject = new Object();
                foodObject.label = data[i][1];
                foodObject.weight = data[i][2];
                foodObject.servingSize = data[i][3];
                foodObject.calories = data[i][4];
                arrayOfObjects.push(foodObject);
            }
        }
    });

    $('#food').autocomplete({
        source: arrayOfObjects,
        select: function (event, ui) {
            selectedObj = ui.item;
            alert("selected object=" + selectedObj.value);
        },
        minLength: 1
    });
})
于 2013-10-07T16:02:23.493 回答