c - 以给定时间频率（计时器）执行功能的最佳方式？

Question

我有一个需要在小型 Linux 嵌入式系统 (ARM) 中运行的小程序。它是用C编写的。它需要从系统制造商提供的API中轮询一些数据（2x64位），然后进行一些计算并通过网络发送数据。数据应每秒轮询约 30 次 (30Hz)。

在 C 中最好的方法是什么？我见过使用 的解决方案sleep()，但它似乎不是这项工作的最佳选择。

Answer 1

I suggest consider using the poll(2) multiplexing syscall to do the polling.

^{notice that when poll is waiting and polling for input, it does not consume any CPU}

If the processing of each event takes some significant time (e.g. a millisecond or more) you may want to recompute the delay.

You could use timerfd_create(2) (and give both your device file descriptor and your timer fd to poll). See also timer_create(2)...

Perhaps clock_gettime(2) could be useful.

And reading time(7) is definitely useful. Perhaps also the Advanced Linux Programming book.

Answer 2

sleep()在几秒钟内暂停执行，如果您正在寻找更准确的类似 sleep() 的函数，请使用usleep()它以微秒或nanosleep()纳秒为单位暂停执行。