1

目前使用 Kohana 3.3 默认路由，如果我说控制器用户和操作登录并且我调用 /user/login，一切都很好，操作被调用并执行。

但现在如果我将 url 更改为 /user/logins，则系统找不到任何名为 logins 的操作并返回错误“Kohana_HTTP_Exception [404]：在此服务器上找不到请求的 URL 用户/登录名”。

我的问题是，如果在控制器中找不到调用的动作，是否有办法强制重定向到 /user/index （默认动作）？

干杯！

4

3 回答 3

2

您可以覆盖 HTTP_Exception_404 类并手动进行重定向。

于 2013-10-07T18:08:50.333 回答
1

EDIT:

So as @Darsstar suggested in comment, it's better to change action in before method in controller than to override execute method. So it goes like this, in your User controller:

protected $default_action = 'index';

public function before()
{
    $action = 'action_'.$this->request->action();
    if (!empty($this->default_action) && !method_exists($this, $action))
    {
        $this->request->action($this->default_action);
    }
}

So if there is no current action and default action is defined it changes current request action to default. You can put this code into main Controller and define only $default_action in subcontrollers.

Old answer:

You should override execute method from Controller class. Normally it looks like this:

public function execute()
{
    // Execute the "before action" method
    $this->before();

    // Determine the action to use
    $action = 'action_'.$this->request->action();

    // If the action doesn't exist, it's a 404
    if ( ! method_exists($this, $action))
    {
        throw HTTP_Exception::factory(404,
            'The requested URL :uri was not found on this server.',
            array(':uri' => $this->request->uri())
        )->request($this->request);
    }

    // Execute the action itself
    $this->{$action}();

    // Execute the "after action" method
    $this->after();

    // Return the response
    return $this->response;
}

Change it to something like this:

public function execute()
{
    // Execute the "before action" method
    $this->before();

    // Determine the action to use
    $action = 'action_'.$this->request->action();

    // If the action doesn't exist, check default action
    if ( ! method_exists($this, $action))
    {
                //Can be hardcoded action_index or $this->default_action set in controller
                $action = 'action_index';

                // If the action doesn't exist, it's a 404
                if ( ! method_exists($this, $action))
                {
                    throw HTTP_Exception::factory(404,
                            'The requested URL :uri was not found on this server.',
                            array(':uri' => $this->request->uri())
                    )->request($this->request);
                }
    }

    // Execute the action itself
    $this->{$action}();

    // Execute the "after action" method
    $this->after();

    // Return the response
    return $this->response;
}

Now if action doesn't exist it checks default action and runs it, or if doesn't exist throws 404.

于 2013-11-15T07:41:43.420 回答
1

实际上你必须重写 HTTP_Exception_404 类。

您可以在那里创建一个 404 NotFound 页面。但是，如果您想重定向到某个页面 - 您需要执行以下操作：

class HTTP_Exception_401 extends Kohana_HTTP_Exception_401 {

/**
 * Generate a Response for the 401 Exception.
 * 
 * The user should be redirect to a login page.
 * 
 * @return Response
 */
    public function get_response() 
    {
        $response = Response::factory()
            ->status(401)
            ->headers('Location', URL::site('user/index'));

        return $response;
    }
}
于 2013-10-08T11:25:29.153 回答