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我有一个 sql 脚本，可以在数据库 (tmp1) 中加载 xml 的文件名。

列表如下所示：

20130918_0932_ZSK40-2.xml
20130918_1032_ZSK70.xml
20130921_0532_ZSK40-2.xml

在另一个脚本中，我想加载每个 xml 文件，以便可以将其导入数据库。

我需要的是选择 tmp1 中的第一个文件名来加载它。

加载文件的脚本部分如下所示：

 SELECT CAST(XmlContent AS XML)
    FROM OPENROWSET(
         BULK 'C:\20130921_0532_ZSK40-2.xml',
         SINGLE_BLOB) AS T(XmlContent)
         ) AS T(XmlContent)

它应该是什么样子？

提前致谢，

IF OBJECT_ID('tempdb..#tmpTable') IS NOT NULL
 DROP TABLE #tmpTable

SELECT machine = XmlContent.value('(/recordedData/machine)[1]', 'varchar(50)'),
 RecordingDate = XmlContent.value('(/recordedData/date)[1]', 'varchar(50)'),
 RecordingTime = XmlContent.value('(/recordedData/hour)[1]', 'varchar(50)'),
 VariableName = XVar.value('(Name)[1]', 'varchar(50)'),
 VariableValue = XVar.value('(Value)[1]', 'varchar(50)')
Into #tmpTable
FROM (

SELECT CAST(XmlContent AS XML)
FROM OPENROWSET(
 BULK 'C:\xml_path_here.xml',
 SINGLE_BLOB) AS T(XmlContent)
 ) AS T(XmlContent)
CROSS APPLY
 XmlContent.nodes('/recordedData/CollectedData/variable') AS XTbl(XVar)

DECLARE @cols AS NVARCHAR(MAX),
 @query AS NVARCHAR(MAX);
SET @cols = STUFF((SELECT distinct ',' + QUOTENAME(c.VariableName) 
 FROM #tmpTable c
 FOR XML PATH(''), TYPE
 ).value('.', 'NVARCHAR(MAX)') 
 ,1,1,'')
set @query = 'SELECT machine, RecordingDate, RecordingTime, ' + @cols + ' from 
 (
 select machine
 , RecordingDate
 , RecordingTime
 , VariableName
 , VariableValue
 from #tmpTable
 ) x
 pivot 
 (
 max(VariableValue)
 for VariableName in (' + @cols + ')
 ) p '


execute(@query)
--SELECT * FROM #tmpTable
drop table #tmpTable
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