0

我想将时间段从“1 小时”更改为“10 分钟”。

并将显示时间从“10”更改为“10:00”

declare @periodStart datetime
declare @periodEnd datetime

set @periodStart =  CONVERT(varchar(10), GETDATE() - 1, 120)
set @periodEnd = CONVERT(varchar(10), GETDATE() , 120) 

set @periodStart = dateadd(HH, datepart(HH,@periodStart), convert(varchar(12),@periodStart,112))
set @periodEnd = dateadd(HH, datepart(HH,@periodEnd), convert(varchar(12),@periodEnd,112))


;with dh
as
(
select top 144 
DATEADD(HOUR,ROW_NUMBER() OVER (ORDER BY [Object_id])-1,convert(varchar(12),@periodStart,112)) as HoDstart,
DATEADD(HOUR,ROW_NUMBER() OVER (ORDER BY [Object_id]),convert(varchar(12),@periodStart,112)) as HoDend,
ROW_NUMBER() OVER (ORDER BY Object_id)-1 as DayHour  
from sys.columns 
)
select d.DayHour, count(f.Hostname) as 'Counter'
from dh d  
left join FileBackup f
on    f.StartTime < d.HoDend 
and f.EndTime >= d.HoDstart  
where d.HoDstart between @periodStart and @periodEnd
group by d.DayHour
order by d.DayHour
4

2 回答 2

1

看看这个帖子。。

http://social.technet.microsoft.com/wiki/contents/articles/17976.t-sql-group-by-time-interval.aspx

我认为该组按小时的 1/6 进行 - 每六分之一小时将是每 10 分钟一次。

重新编写查询，我们应该从上一个答案中看到：

SELECT  DATEPART(minute, logtime)/6 AS [SixthHour],
           COUNT(loginid) AS [Logins Completed]
FROM    somelog
GROUP BY DATEPART(minute, logtime)/6

这应该有帮助 - http://sqlfiddle.com/#!3/f60f3/1

于 2013-10-07T03:59:40.597 回答
0

带有想要的标签等，基于 Leptonator 的分钟/6 示例

DECLARE @periodStart datetime
DECLARE @periodEnd datetime

SET @periodStart = dateadd(DAY, datediff(DAY,0, GETDATE()), -1)
SET @periodEnd   = dateadd(DAY, datediff(DAY,0, GETDATE()), 0)

SELECT
        convert(varchar(5),dateadd(MINUTE,number*10,'00:00:00'),8) AS label
      , x.Logins_Completed
FROM master..spt_values AS t1
LEFT JOIN (
            SELECT
                     DATEPART(MINUTE, logtime)/6 AS [SixthHour]
                   , COUNT(loginid) AS [Logins_Completed]
            FROM    somelog
            WHERE ( logtime >= @periodStart AND logtime < @periodEnd )
            GROUP BY DATEPART(MINUTE, logtime)/6
          ) AS x ON t1.number = x.SixthHour
WHERE t1.type = 'P'
AND t1.number between 0 and 143;

看到这个 sqlfiddle

额外的观察：

不知道为什么要设置两次日期参数：以下两个参数的值与现有参数的值相同：

/* easier to read */
declare @periodStart datetime
declare @periodEnd datetime

set @periodStart = CONVERT(varchar(10), GETDATE() - 1, 120)
set @periodEnd   = CONVERT(varchar(10), GETDATE() , 120) 

select 
      @periodStart
    , @periodEnd
;

/* faster */
declare @periodStart datetime
declare @periodEnd datetime

set @periodStart = dateadd(day, datediff(day,0, GETDATE()), -1)
set @periodEnd   = dateadd(day, datediff(day,0, GETDATE()), 0)

select 
      @periodStart
    , @periodEnd
;

此外，您可能需要重新考虑使用 'between' 作为日期范围选择方法：

where ( d.HoDstart >= @periodStart and d.HoDstart < @periodEnd )

请参阅：BETWEEN 和魔鬼有什么共同点？

于 2013-10-07T05:30:54.360 回答