sql - Oracle SQL 比较日期

Question

SQL> select * from porder ;

   OID       BILL ODATE
  ------ ---------- ---------
    10        200 06-OCT-13
     4      39878 05-OCT-13
     5     430000 05-OCT-13
    11        427 06-OCT-13
    12        700 06-OCT-13
    14      11000 06-OCT-13
    15      35608 06-OCT-13
    13      14985 06-OCT-13
     8      33000 06-OCT-13
     9        600 06-OCT-13
    16        200 06-OCT-13

   OID       BILL ODATE
------ ---------- ---------
     1        200 04-OCT-13
     2      35490 04-OCT-13
     3       1060 04-OCT-13
     6        595 05-OCT-13
     7        799 05-OCT-13

16 rows selected.  

 SQL> select * from porder where odate='04-Oct-2013';

no rows selected

请有人帮忙...为什么查询不起作用..??

Answer 1

In Oracle, a DATE always has a time component. Your client may or may not display the time component, but it is still there when you try to do an equality comparison. You also always want to compare dates with dates rather than strings which use the current session's NLS_DATE_FORMAT for doing implicit conversions thus making them rather fragile. THat will involve either ANSI date literals or explicit to_date calls

You can use the TRUNC function to truncate the DATE to midnight

SELECT *
  FROM porder
 WHERE trunc(odate) = date '2013-10-04'

Or you can do a range comparison (which will be more efficient if you can benefit from an index on odate)

SELECT *
  FROM porder
 WHERE odate >= to_date( '04-Oct-2013', 'DD-Mon-YYYY' )
   AND odate <  to_date( '05-Oct-2013', 'DD-Mon-YYYY' );