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我想删除我添加的数据库中的一行，但是当我尝试单击 index.php 中的删除按钮时，它说记录已删除，但是当我单击确定时，它不会删除记录，这是我的代码：

index.php：

$con = mysql_connect("localhost","pma");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("class_schedule", $con);

$result = mysql_query("SELECT * FROM schedule");

?>
<center>
<table border="1" width="800">
<tr>
<td colspan='8'><input type="text" width='300'/>
<input type="button" value="Search" onclick="location='search.php'" />
<input type="button" value="View All" onclick="window.location.href=''"/>
<input type="button" value="Add" onclick="location='add.php'"/></td>
</tr></table>

<?php
echo "<center><table border='1' width='800'>
<tr>
    <td><center>Time</td>
        <td><center>Subject</td>
    <td><center>Course</td>
    <td><center>Section</td>
        <td><center>Day</td>
    <td><center>Room</td>

</tr>";

while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['time'] . "</td>";
echo "<td>" . $row['subject'] . "</td>";
echo "<td>" . $row['course'] . "</td>";
echo "<td>" . $row['section'] . "</td>";
echo "<td>" . $row['day'] . "</td>";
echo "<td>" . $row['room'] . "</td>";

?>


<td><input type="submit" value="Edit" name="edit" />
<form action="delete.php" method="post">
<input type="submit" value="Delete" name="delete" onclick="location='delete.php'" />
</td>
</form>
<?php
echo "</tr>";
}
echo "</table></center>";

mysql_close($con);
?>

这是我的delete.php：

<?php

    require "connect.php";
    $deltime=$_POST["deltime"];
    mysql_query("DELETE FROM schedule WHERE deltime='$deltime'");
    mysql_close($con);
?>
<div>
<p align="center"><b>Record Deleted</b><br/>
<form method="post">
    <center><input type="submit" name="submit" value="Ok" formaction="index.php" /></center>
</form>
</p></div></form>

我错过了什么，我应该删除和添加什么？

4

3 回答 3

1

您的 id 没有进入delete.php文件，所以只需删除您的删除按钮并替换为以下代码：

<td><a href="delete.php? id=<?php echo $row['id'];?>">Delete</td>
于 2014-05-08T09:37:00.233 回答
0

尝试通过一个链接将日期发送到delete.php

<td><a href = 'delete.php'?date=<?php echo $row['time'];?>>DELETE</a></td>
于 2014-10-25T07:52:00.850 回答
0

修改以下行

mysql_query("DELETE FROM schedule WHERE deltime='$deltime'");

作为

mysql_query("DELETE FROM schedule WHERE deltime='$deltime'", $con);
于 2014-05-08T09:23:27.997 回答