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我正在尝试从输入文件中获取字符，但我无法真正让它工作，谁能帮助我解决这个问题？我提前为格式道歉，这让我很困惑。

open_input_and_output_file基本上检查您是否可以打开文件，并且在 OTP 中，我试图将每个字符从一个文件获取到另一个文件。由于我无法让它工作，我首先尝试在控制台应用程序中显示这些字符，但这也不起作用。

任何帮助将不胜感激，我希望提供的信息足够。

    bool open_input_and_output_file(ifstream& infile, ofstream& outfile)
{
//Precondition: True
assert(true);
//Postcondition: Inputfile and outputfile have either been opened succesfully or you have been notified of it not opening succesfully.
string inputfile;
string outputfile;
cout<<"\nPlease enter an input-file name (no spaces): ";
cin>>inputfile;
cout<<"NOTE: Input-file name and output-file name can NOT be the same!"<<endl;
cout<<"Please enter an output-file name (no spaces): ";
cin>>outputfile;
if(inputfile != outputfile)
{
    cout<<"Input-file name and output-file name are not the same! Good job on reading!"<<endl;
    ifstream infile(inputfile.c_str());
    if(infile)
        cout<<"Input-file: "<<inputfile<<" was opened succesfully!"<<endl;
    if(!infile)
        cout<<"Inputfile: "<<inputfile<<" could not be opened!"<<endl;
    ofstream outfile(outputfile.c_str());
    if(outfile)
        cout<<"Output-file: "<<outputfile<<" was opened succesfully!"<<endl;
    if(!outfile)
        cout<<"Outputfile: "<<outputfile<<" could not be opened!"<<endl;
}

else
{
    cout<<"Input-file name and output-file name are the same!"<<endl;
    cout<<"Opening has failed!"<<endl;
}
return 0;
}
void OTP(ifstream& infile, ofstream& outfile)
{
int choice;
char character;
unsigned int r;
srand(r);

cout<<"\nPlease enter 0 to encrypt or 1 to decrypt: ";
cin>>choice;
if(open_input_and_output_file(infile,outfile))
{
    infile.get(character);
    cout<<character;
}


}
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1 回答 1

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我会说错误就在这里

cout<<"Input-file name and output-file name are not the same! Good job on reading!"<<endl;
ifstream infile(inputfile.c_str());

应该

cout<<"Input-file name and output-file name are not the same! Good job on reading!"<<endl;
infile.open(inputfile.c_str());

你对outfile犯了同样的错误。

ofstream outfile(outputfile.c_str());

应该

outfile.open(outputfile.c_str());

您将 infile 和 outfile 作为参数传递给您的open_input_and_output_file函数，然后在函数中再次声明它们。因此，当您打开文件时，您没有使用传递给的流open_input_and_output_file，而是使用该函数本地的流。溪流通过以open_input_and_output_file保持关闭。

于 2013-10-06T11:13:12.543 回答