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我希望使用 MVC 4 为我的博客提供一条 SEO 友好的路线。我查看了几篇 stackoverflow 文章并尝试使用该建议，但我仍然无法使其正常工作。

我尝试做的是当有人点击其中一篇博客文章时，路线显示：blog/{blogCategory}/{blogTitle}，例如“blog/cleaning/how-to-remove-stains”。我错过了一些重要的东西。我已经包含了控制器、视图和路由。我有两个问题：

  1. 为什么当我将 blogTitle（“西班牙的雨”）传递给控制器​​时，它带有连字符和空格？我希望能够获取标题并通过一个函数运行它以使其 URL 友好并将其放回以显示在路由中。

  2. 为什么该路线仅部分有效？而不是显示 blog/{blogCategory}/{blogTitle} 它显示 blog/{blogCategory}?querystrings 见下面的例子： blog/uncategorized/the%20-rain%20in%20-spain%20-falls%20-mainly%20on %20the%20-plains?id=2。（注：未分类为分类之一）

路线配置：

public class RouteConfig
    {

        public static void RegisterRoutes(RouteCollection routes)
        {
            routes.Canonicalize().NoWww().Pattern("([a-z0-9])([A-Z])", "$1-$2").Lowercase().NoTrailingSlash();

            routes.IgnoreRoute("{resource}.axd/{*pathInfo}");

            routes.MapRoute(
            "Blog",
            "Blog/{blogCategory}/{blogTitle}",
            new { controller = "Blog", action = "Details" }
            ).RouteHandler = new Spotless_Interiors.Models._GlobalClasses.HyphenatedRouteHandler();

            // Original route map
            routes.MapRoute(
                name: "Default",
                url: "{controller}/{action}/{id}",
                defaults: new { controller = "Home", action = "Index", id = UrlParameter.Optional }
            ).RouteHandler = new Spotless_Interiors.Models._GlobalClasses.HyphenatedRouteHandler(); 


        }
    }

看法：

@model Spotless_Interiors.Models.MultiModels

@{
    ViewBag.Title = "Blog";
    ViewBag.Separator = " | ";
    ViewBag.Path = Request.Path;

}


@section menuLeft {
    @Html.Partial("_BlogMenu")
}
@Html.Partial("_TitleBlockPartial", Model.Company)

@if (User.Identity.IsAuthenticated) {
    <div class="blog-links">            
        @Html.ActionLink("Create New", "Create", "Blog", new { DT_Stamp = @DateTime.Now })
        @ViewBag.Separator
        <a href="@Url.Action("Meta-Tag-Editor", "Dashboard", new { pageName = (string)ViewBag.pageName, path = (string)ViewBag.Path })" >MetaTag</a> 
        <hr />
    </div> 
}

<div id="blog">
    @foreach (var item in Model.PagedPosts)
    {


            <h1>@Html.ActionLink(item.Title, "Details", new { id = item.PostID, blogCategory = item.Category.CategoryName, blogTitle = item.Title }, new { @class ="blog-title" }) </h1>  

            <div class="full-width">
                <div class="blog-category">  
                    <h2>@Html.DisplayFor(modelItem => item.Category.CategoryName) |  @Html.DisplayFor(modelItem => item.DT_Stamp)</h2> 
                </div>
                <div class="blog-links"> 
                    @Html.ActionLink("Read More >>", "Details", new { id = item.PostID, blogCategory = item.Category.CategoryName, blogTitle = item.Title }, new { @class ="blog-links" })
                </div>
            </div>
            <div class="full-width">

            </div>
                @Html.Raw(Server.HtmlDecode(item.TruncatedBody.Replace("<img ", "<img style = 'width:100px' ")))


            <div class="ribbon" style="clear:both"></div>            

    }
</div>

控制器：

// GET: /Blog/Details
        public ActionResult Details(int id = 0, string blogCategory = "", string blogTitle = "")
        {
            pageName = "Blog Details";
            ViewBag.pageName = pageName;
            var multiModels = _globalClasses.Standard(ViewBag.pageName, Request.Path);

            ///multiModels.Post = db.Posts.First(i => i.PostID == id);
            multiModels.Post = db.Posts.First(i => i.PostID == id);
            multiModels.PostComments = db.PostComments.Where(i => i.PostPostID == id).ToList();


            blogTitle = _globalClasses.UrlFriendly(blogTitle);


            if (multiModels.Post == null)
            {                
                return HttpNotFound();
            }

            return View(multiModels);
        }
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1 回答 1

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也许您的自定义扩展方法Canonicalize（？）和自定义路由处理程序搞砸了。

关于 ASP.NET MVC，这就足够了：

public static void RegisterRoutes(RouteCollection routes)
{
    routes.IgnoreRoute("{resource}.axd/{*pathInfo}");

    routes.MapRoute(name:"Blog", url:"Blog/{blogCategory}/{blogTitle}",
                    defaults:new {controller = "Blog", action = "Details"});

    routes.MapRoute(name:"Default", url:"{controller}/{action}/{id}",
                    defaults:new {controller = "Home", action = "Index", id = UrlParameter.Optional});
}

和控制器：

public class BlogController : Controller
{
    public ActionResult Details(string blogCategory, string blogTitle)
    {
        return Content(string.Format("category: {0}, title: {1}", blogCategory, blogTitle));
    }
}

对于路径/blog/my%20category/my%20title，您会得到正确的响应"category: my category, title: my title"。

于 2013-10-05T16:21:27.260 回答