0

我有一个具有以下架构的 MySql 表。 

table_products - "product_id", product_name, product_description, product_image_path, brand_id
table_product_varient - "product_id", "varient_id", product_mrp, product_sellprice, product_imageurl
table_varients - "varient_id", varient_name
table_product_categories - "product_id", "category_id"

用户正在传递一个 category_id，我正在使用该类别获取所有项目

my $sql_query = "SELECT
P.product_id, P.product_name,  V.varient_name, PV.product_mrp, PV.product_sellprice, P.product_image_path
FROM
table_products as P
INNER JOIN
table_product_categories as PC 
ON
  P.product_id = PC.product_id
INNER JOIN
table_product_varients as PV
ON
P.product_id = PV.product_id
INNER JOIN
table_varients as V
ON
V.varient_id = PV.varient_id
where 
PC.category_id = '$cate_id' ";

我想修改这个查询，如果 product_imageurl 在 table_product_varients 中可用，则获取该图像，否则从 table_products 获取 product_image_path 图像。目前查询正在从 table_products 中获取 product_image_path 图像。

可以请有人帮助我。

任何帮助将不胜感激。

4

2 回答 2

2

您可以避免这种情况：

SELECT
    P.product_id, 
    P.product_name, 
    V.varient_name, 
    PV.product_mrp, 
    PV.product_sellprice, 
    IFNULL(PV.product_imageurl, P.product_image_path) AS product_imageurl
FROM
    table_product_categories PC,
    table_varients V, 
    table_products P
        LEFT JOIN table_product_varients PV ON P.product_id = PV.product_id
where 
    P.product_id = PC.product_id
    AND V.varient_id = PV.varient_id
    AND PC.category_id = '$cate_id'
于 2013-10-05T04:58:46.820 回答
1

替换这个

P.product_image_path

和

CASE 
  WHEN PV.product_imageurl IS NULL OR PV.product_imageurl = '' then
       P.product_image_path
ELSE 
     PV.product_imageurl
END
于 2013-10-05T04:57:52.237 回答