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我有一个 REST API，允许客户端使用 Linkedin 登录，并从 Linkedin 传递访问令牌。

我通过从Javascript API获取访问令牌并发送登录来创建此服务，而不是 api 调用 LinkedIn API 来检索用户数据。这工作正常，但我们在使用 iOS 生成的访问令牌时遇到了问题。

我们正在使用LinkedIn OAuth 示例客户端在移动设备上登录 LinkedIn，然后获得访问令牌。使用该访问令牌，我们的 API 无法调用 LinkedIn。

我的问题是：这是在 API 中使用 LinkedIn API 的正确方法吗？而且，如果是，我如何在 iOS 集成中生成正确的访问令牌到我的 API 可以使用它？

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1 回答 1

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您需要遵循简单的步骤。
1.您需要向LinkedIn申请用户授权。（authorisation code将在此处收到作为响应。）
2. 使用您需要使用上面收到的授权码向linkedIn 发出POST 请求authorisation code。

在ViewDidLoad 

-(void)viewDidLoad  
{  
#warning:- Please provide your clientID and clientSecret
linkedInKey = @"YOUR_CLIENT_ID_HERE";
linkedInSecret = @"YOUR_CLIENT_SECRET_HERE";
authorizationEndPoint = @"https://www.linkedin.com/uas/oauth2/authorization";
accessTokenEndPoint = @"https://www.linkedin.com/uas/oauth2/accessToken";  
#warning:- Please provide your redirectUrl here.
NSString *redirectURL = @"http://REDIRECT_URL_THAT_YOU_HAVE_PROVIDED_WHILE_REGISTERING_YOUR_APP";
encodedRdirectURL = [redirectURL stringByAddingPercentEncodingWithAllowedCharacters:NSCharacterSet.alphanumericCharacterSet];
_webView.delegate = self;
[self startAuthorisation];
}

-(void)startAuthorisation
{
// Specify the response type which should always be "code".
NSString *responseType = @"code";
// Create a random string
NSString *state = @"anyRandomString";
// Set preferred scope. It depends on your preference.
NSString *scope = @"w_share";
// Create the authorization URL string.
NSString *authorizationURL = [NSString stringWithFormat:@"%@?response_type=%@&client_id=%@&redirect_uri=%@&state=%@&scope=%@",authorizationEndPoint,responseType,linkedInKey,encodedRdirectURL,state,scope];

NSLog(@"%@",authorizationURL);
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:authorizationURL]];
[_webView loadRequest:request];
}

#pragma mark- WebView Delegate.

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
{
NSURL *url = request.URL;
//here we will catch the response of the server which will redirect to our redirect url. Hence we first check for the host(which is our redirect url) then only extract the code.  
#warning:- Please provide your redirectUrl here.
if ([url.host isEqualToString:@"www.Your_redirect_url.com"])
{
    if ([url.absoluteString rangeOfString:@"code"].length)
    {

//response containing the authorisation code looks somehow like below.
    //http://www.Your_redirect_url.com?<strong>code=AQSetQ252oOM237XeXvUreC1tgnjR-VC1djehRxEUbyZ-sS11vYe0r0JyRbe9PGois7Xf42g91cnUOE5mAEKU1jpjogEUNynRswyjg2I3JG_pffOClk</strong>&state=linkedin1450703646

   //......obtaining the code from the response......//
        NSArray *urlParts = [url.absoluteString componentsSeparatedByString:@"?"];
        NSString *codePart = [urlParts objectAtIndex:1];
        NSArray *codeParts = [codePart componentsSeparatedByString:@"="];
        NSString *code = [codeParts objectAtIndex:1];
        [self requestforAccessToken:code];
    }
}
return YES;
}

- (void)requestforAccessToken:(NSString *)authorisationCode
{
NSString *grantType = @"authorization_code";
NSString *postParameter = [NSString stringWithFormat:@"grant_type=%@&code=%@&redirect_uri=%@&client_id=%@&client_secret=%@",grantType,authorisationCode,encodedRdirectURL,linkedInKey,linkedInSecret];
NSData *postdata = [postParameter dataUsingEncoding:NSUTF8StringEncoding];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc]initWithURL:[NSURL URLWithString:accessTokenEndPoint]];
request.HTTPMethod = @"POST";
request.HTTPBody = postdata;
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];

AFURLSessionManager *manager = [[AFURLSessionManager alloc] initWithSessionConfiguration:[NSURLSessionConfiguration defaultSessionConfiguration]];


manager.responseSerializer = [AFJSONResponseSerializer
                              serializerWithReadingOptions:NSJSONReadingAllowFragments];


[[manager dataTaskWithRequest:request completionHandler:^(NSURLResponse  * response, id  responseObject, NSError * error )
  {
      if (!error)
      {
          NSLog(@"Reply JSON: %@", responseObject);
          NSString *accessToken = [responseObject objectForKey:@"access_token"];
          NSUserDefaults *defaults = [NSUserDefaults standardUserDefaults];
          [defaults setObject:accessToken forKey:@"linkedInAccessToken"];
          [defaults synchronize];
      }

  }] resume];

}

我在这里使用了 AFNetworking 库。因此，请从 gitHub 获取库并将其添加到您的项目中。AFHTTPSessionManager.h为此，您需要在 viewController 中导入。

#warning:- please declare these following strings as global variable under interface as.  
@interface WebViewController ()<UIWebViewDelegate>  
{
NSString *linkedInKey;
NSString *linkedInSecret;
NSString *authorizationEndPoint;
NSString *accessTokenEndPoint;
NSString *encodedRdirectURL;    
}

而且我还使用了 a并用 nameUIWebView连接到它，你可以在上面的代码中找到它。 IBOutletwebView

不要忘记确认 UIWebViewDelegate。

希望这会有所帮助。
祝你好运。

于 2016-04-30T11:43:52.477 回答