php - PHP: json_decode

Question

我必须从这样的 json 字符串中解析值：

[{"type":"list","value":["A","B"],"field":"scheda"}] 

如何使用 PHP 函数做到这一点json_decode？

例如我想打印：

field = "scheda"
values = "A,B"

Answer 1

$json = json_decode('[{"type":"list","value":["A","B"],"field":"scheda"}]');
print 'field = "'.$json[0]->field.'"'."\n";
print 'values = "'.implode(",",$json[0]->value).'"'."\n";

Answer 2

如果你不能使用json_decode()，为什么不尝试一个类？

例如，类似... http://www.phpclasses.org/package/4205-PHP-Serialize-and-unserialize-values-in-JSON-format.html