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我正在寻找一种使以下日期格式更具可读性的轻量级方法。

04OCT2013

理想情况下，我希望它输出：

4 October 2013

任何帮助将不胜感激，谢谢！

4

6 回答 6

1

您首先需要解析您的字符串，然后格式化它的各个部分。您可以为此使用一些成熟的库（有一些），或者自己编写两个简单的函数：

var shortMonths = ["jan","feb","mar","apr","may","jun","jul","aug","sep","oct","nov","dez"],
    longMonths = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
function parse(datestring) {
    var date = parseInt(datestring.slice(0,2), 10),
        month = shortMonths.indexOf(datestring.slice(2,5).toLowerCase()),
        year = parseInt(datestring.slice(5,9), 10);
    return new Date(year, month, date);
}
function format(date) {
    return [date.getDate(), longMonths[date.getMonth()], date.getFullYear()].join(" ");
}


> format(parse("04OCT2013"))
"4 October 2013"
于 2013-10-04T11:10:00.790 回答
1

灵感来自 Bergi 的回答：

function formatDate(s) {
  s = s.toLowerCase().match(/\d+|\D+/g);
  var months = {jan:'January', feb:'February', mar:'March', apr:'April',
                may:'May', jun:'June', jul:'July', aug:'August', sep:'September',
                oct:'October', nov:'November', dec:'December'};
  return +s[0] + ' ' + months[s[1]] + ' ' + s[2]; 
}

formatDate('04OCT2013'); // 4 October 2013
formatDate('14NOV2015'); // 14 November 2015
于 2013-10-04T11:35:37.520 回答
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您可以尝试使用moment.js

<script src="//cdn.jsdelivr.net/momentjs/2.0.0/moment.min.js"></script>

var date = new Date("04OCT2013");
var newDate = moment(date).format("DD MMMM YYYY");

alert(newDate);

Js 小提琴演示

于 2013-10-04T11:03:53.767 回答
0 
 var months= [ "January", "February", "March", "April", "May", "June", "July", "August",  "September", "October", "November", "December" ];
 var d = new Date();
 var desc = d.getDate() + ' ' + months[d.getMonth()] + ' ' + d.getFullYear();

但我会建议 date.js 甚至更好的 moment.js。

于 2013-10-04T11:08:29.907 回答
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var now = new Date();
var monthNamesL = [ "January", "February", "March", "April", "May", "June",
                    "July", "August", "September", "October", "November", "December" ],
    monthNamesS = [ "Jan", "Feb", "Mar", "Apr", "May", "Jun",
                    "Jul", "Aug", "Sep", "Oct", "Nov", "Dec" ];

var dateFmtd = monthNamesL[now.getMonth()] + ' ' + now.getDay() + ', ' + now.getFullYear();
alert(dateFmtd);
于 2013-10-04T11:09:00.390 回答
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Jsut 稍微格式化字符串并使用内置的Date 类型和 parse ：

var myString = "04OCT2013";

然后子串出第一个字符，最后 4 个和月份，这样你就可以使用内置的解析器，如下所示：

Date.parse("Aug 9, 1995");

无需创建自己的月份数组。

于 2013-10-04T11:49:45.470 回答