我编写了一个 python 代码来获取与给定 url 对应的网页,并将该页面上的所有链接解析到链接存储库中。接下来,它从刚刚创建的存储库中获取任何 url 的内容,将新内容中的链接解析到存储库中,并继续对存储库中的所有链接进行此过程,直到停止或获取给定数量的链接之后。
这里代码:
import BeautifulSoup
import urllib2
import itertools
import random
class Crawler(object):
"""docstring for Crawler"""
def __init__(self):
self.soup = None # Beautiful Soup object
self.current_page = "http://www.python.org/" # Current page's address
self.links = set() # Queue with every links fetched
self.visited_links = set()
self.counter = 0 # Simple counter for debug purpose
def open(self):
# Open url
print self.counter , ":", self.current_page
res = urllib2.urlopen(self.current_page)
html_code = res.read()
self.visited_links.add(self.current_page)
# Fetch every links
self.soup = BeautifulSoup.BeautifulSoup(html_code)
page_links = []
try :
page_links = itertools.ifilter( # Only deal with absolute links
lambda href: 'http://' in href,
( a.get('href') for a in self.soup.findAll('a') ) )
except Exception: # Magnificent exception handling
pass
# Update links
self.links = self.links.union( set(page_links) )
# Choose a random url from non-visited set
self.current_page = random.sample( self.links.difference(self.visited_links),1)[0]
self.counter+=1
def run(self):
# Crawl 3 webpages (or stop if all url has been fetched)
while len(self.visited_links) < 3 or (self.visited_links == self.links):
self.open()
for link in self.links:
print link
if __name__ == '__main__':
C = Crawler()
C.run()
此代码不获取内部链接(仅绝对形式的超链接)
如何获取以“/”或“#”或“。”开头的内部链接