1

嗨，我创建了一个 cron 作业，并且通过使用它运行良好

org.springframework.scheduling.quartz.SimpleTriggerBean

但是当我使用 CronTrigger 安排我的工作时，这个工作根本没有触发，它也没有抛出任何错误，下面是我的 spring 配置和 Job 类。

<bean id="cronJobTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean">
        <property name="jobDetail" ref="runBillingJob" />
        <property name="cronExpression" value="0 0 0 * * ?"/>
</bean>

    <bean class="org.springframework.scheduling.quartz.SchedulerFactoryBean">
        <property name="jobDetails">
            <list>
                <ref bean="runTestJob" />
            </list>
        </property>

        <property name="triggers">
            <list>
                <ref bean="cronJobTrigger" />
            </list>
        </property>
    </bean>

以下是我的测试方法：

@SuppressWarnings("unchecked")
protected void executeInternal(JobExecutionContext context)
        throws JobExecutionException {
    List<JobExecutionContext> jobs = null;
    try {
        jobs = context.getScheduler().getCurrentlyExecutingJobs();
        for (JobExecutionContext job : jobs) {
            if (job.getTrigger().equals(context.getTrigger())
                    && !job.getJobInstance().equals(this)) {
                logger.trace("There's another instance running, so leaving: "
                        + this);
                return;
            }
        }
        logger.info("Create a BillingService instance...");

    } catch (SchedulerException e) {
        logger.error("", e);
        return;
    }

    try {
        triggerToController();
    } catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
4

1 回答 1

0

尝试这个：

    <bean id="cronJobTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean">
        <property name="jobDetail" ref="runBillingJob" />
        <property name="cronExpression" value="0 0 0 * * ?"/>
    </bean>
    <bean id="runBillingJob" class="org.springframework.scheduling.quartz.JobDetailBean">
        <property name="jobClass" value="your.package.YourClass" />
    </bean>
    <bean class="org.springframework.scheduling.quartz.SchedulerFactoryBean">
        <property name="triggers">
            <list>
                <ref bean="cronJobTrigger" />
            </list>
        </property>
    </bean>
于 2013-10-17T22:59:44.930 回答