5

我使用 Bing Map REST API，因为我想从特定位置找出地理位置。Url 效果很好，但由于事实上，我第一次使用 JSON 代码，我真的不知道如何获得我想要的输出。

我尝试了以下方法：

string URL = "http://dev.virtualearth.net/REST/v1/Locations?countryRegion=&adminDistrict=&locality=Wien&postalCode=&addressLine=&userLocation=&userIp=&usermapView=&includeNeighborhood=&maxResults=&key=MY_KEY";
WebClient client = new WebClient();
client.OpenReadAsync(new Uri(URL, UriKind.Absolute));
client.OpenReadCompleted += new OpenReadCompletedEventHandler(client_OpenReadCompleted);

private void client_OpenReadCompleted(object sender, OpenReadCompletedEventArgs e)
{
    DataContractJsonSerializer serializer = new DataContractJsonSerializer(typeof(Point));
    Point data = serializer.ReadObject(e.Result) as Point;
}

[DataContract]
public class Point
{
    /// <summary>
    /// Latitude,Longitude
    /// </summary>
    [DataMember(Name = "coordinates")]
    public double[] Coordinates { get; set; }
}

当我在浏览器中输入链接时，这是我的回应：

{"authenticationResultCode":"ValidCredentials","brandLogoUri":"http://dev.virtualearth.net/Branding/logo_powered_by.png","copyright":"版权所有 © 2013 Microsoft 及其供应商。保留所有权利。此未经微软公司明确书面许可，不得访问 API，不得以任何方式使用、复制或传输内容和任何结果。","re​​sourceSets":[{"estimatedTotal":1,"resources":[{" __type":"位置：http://schemas.microsoft.com/search/local/ws/rest/v1","bbox":[47.253395080566406,-123.16571807861328,47.946159362792969,-121.50344085693359],"名称":"西雅图, WA","point":{"type":"Point","coordinates":[47.603561401367188,-122.32943725585938]},"address":{"adminDistrict":"WA","adminDistrict2":"King Co.","countryRegion":"United States","formattedAddress":"Seattle, WA","locality": "Seattle"},"confidence":"High","entityType":"PopulatedPlace","geocodePoints":[{"type":"Point","coordinates":[47.603561401367188,-122.32943725585938],"calculationMethod": "屋顶","usageTypes":["Display"]}],"matchCodes":["Good"]}]}],"statusCode":200,"statusDescription":"OK","traceId":"08bee37ecb714d7cb7e2783eb8f873a4 |LTSM000177|02.00.183.2300|LTSIPEVM000039"}adminDistrict":"WA","adminDistrict2":"King Co.","countryRegion":"United States","formattedAddress":"Seattle, WA","locality":"Seattle"},"confidence":" High","entityType":"PopulatedPlace","geocodePoints":[{"type":"Point","coordinates":[47.603561401367188,-122.32943725585938],"calculationMethod":"Rooftop","usageTypes":["显示"]}],"matchCodes":["Good"]}]}],"statusCode":200,"statusDescription":"OK","traceId":"08bee37ecb714d7cb7e2783eb8f873a4|LTSM000177|02.00.183.2300|LTSIPEVM000039"}adminDistrict":"WA","adminDistrict2":"King Co.","countryRegion":"United States","formattedAddress":"Seattle, WA","locality":"Seattle"},"confidence":" High","entityType":"PopulatedPlace","geocodePoints":[{"type":"Point","coordinates":[47.603561401367188,-122.32943725585938],"calculationMethod":"Rooftop","usageTypes":["显示"]}],"matchCodes":["Good"]}]}],"statusCode":200,"statusDescription":"OK","traceId":"08bee37ecb714d7cb7e2783eb8f873a4|LTSM000177|02.00.183.2300|LTSIPEVM000039"}countryRegion":"United States","formattedAddress":"Seattle, WA","locality":"Seattle"},"confidence":"High","entityType":"PopulatedPlace","geocodePoints":[{" type":"Point","coordinates":[47.603561401367188,-122.32943725585938],"calculationMethod":"Rooftop","usageTypes":["Display"]}],"matchCodes":["Good"]}]} ],"statusCode":200,"statusDescription":"OK","traceId":"08bee37ecb714d7cb7e2783eb8f873a4|LTSM000177|02.00.183.2300|LTSIPEVM000039"}countryRegion":"United States","formattedAddress":"Seattle, WA","locality":"Seattle"},"confidence":"High","entityType":"PopulatedPlace","geocodePoints":[{" type":"Point","coordinates":[47.603561401367188,-122.32943725585938],"calculationMethod":"Rooftop","usageTypes":["Display"]}],"matchCodes":["Good"]}]} ],"statusCode":200,"statusDescription":"OK","traceId":"08bee37ecb714d7cb7e2783eb8f873a4|LTSM000177|02.00.183.2300|LTSIPEVM000039"}entityType":"PopulatedPlace","geocodePoints":[{"type":"Point","coordinates":[47.603561401367188,-122.32943725585938],"calculationMethod":"Rooftop","usageTypes":["Display"]} ],"matchCodes":["Good"]}]}],"statusCode":200,"statusDescription":"OK","traceId":"08bee37ecb714d7cb7e2783eb8f873a4|LTSM000177|02.00.183.2300|LTSIPEVM000039"}entityType":"PopulatedPlace","geocodePoints":[{"type":"Point","coordinates":[47.603561401367188,-122.32943725585938],"calculationMethod":"Rooftop","usageTypes":["Display"]} ],"matchCodes":["Good"]}]}],"statusCode":200,"statusDescription":"OK","traceId":"08bee37ecb714d7cb7e2783eb8f873a4|LTSM000177|02.00.183.2300|LTSIPEVM000039"}statusDescription":"OK","traceId":"08bee37ecb714d7cb7e2783eb8f873a4|LTSM000177|02.00.183.2300|LTSIPEVM000039"}statusDescription":"OK","traceId":"08bee37ecb714d7cb7e2783eb8f873a4|LTSM000177|02.00.183.2300|LTSIPEVM000039"}

我现在的问题是：这是正确的方法吗？我如何获取数据？

我希望你能帮助我，我已经花了很多时间来解决这个问题。

- - -编辑 - - -

现在我使用 JSON.net，但我不知道如何将从网站获得的数据解析为字符串变量。

我尝试了以下方法：

var json = new WebClient().DownloadString("url");

但这不起作用，因为我正在 Windows Phone 上开发。

System.Net.WebClient 不包含“DownloadString”的定义......

任何人都可以帮助我使其适用于 Windows Phone 应用程序。

4

4 回答 4

7

使用 json 时，我更喜欢Json.Net。在声明了必要的类之后，这段代码就是

var root = JsonConvert.DeserializeObject<RootObject>(json);

foreach (var rs in root.resourceSets)
{
    foreach (var r in rs.resources)
    {
        Console.WriteLine(r.point.coordinates[0] + " , " + r.point.coordinates[1]);
    }
}

您可以使用此站点将您的 json 转换为具体的类

public class Point
{
    public string type { get; set; }
    public List<double> coordinates { get; set; }
}

public class Address
{
    public string adminDistrict { get; set; }
    public string adminDistrict2 { get; set; }
    public string countryRegion { get; set; }
    public string formattedAddress { get; set; }
    public string locality { get; set; }
}

public class GeocodePoint
{
    public string type { get; set; }
    public List<double> coordinates { get; set; }
    public string calculationMethod { get; set; }
    public List<string> usageTypes { get; set; }
}

public class Resource
{
    public string __type { get; set; }
    public List<double> bbox { get; set; }
    public string name { get; set; }
    public Point point { get; set; }
    public Address address { get; set; }
    public string confidence { get; set; }
    public string entityType { get; set; }
    public List<GeocodePoint> geocodePoints { get; set; }
    public List<string> matchCodes { get; set; }
}

public class ResourceSet
{
    public int estimatedTotal { get; set; }
    public List<Resource> resources { get; set; }
}

public class RootObject
{
    public string authenticationResultCode { get; set; }
    public string brandLogoUri { get; set; }
    public string copyright { get; set; }
    public List<ResourceSet> resourceSets { get; set; }
    public int statusCode { get; set; }
    public string statusDescription { get; set; }
    public string traceId { get; set; }
}

Json.net 还允许您在dynamic不声明任何这些类的情况下使用关键字。

dynamic root = JsonConvert.DeserializeObject(json);

foreach (var rs in root.resourceSets)
{
    foreach (var r in rs.resources)
    {
        Console.WriteLine(r.point.coordinates[0] + " , " + r.point.coordinates[1]);
    }
}
于 2013-10-03T18:31:11.477 回答
3

您可以使用 Microsoft JSON 序列化器/反序列化器。

如果您不使用 ASP.NET，则需要包含 System.Web 和 System.Web.Extensions 引用；

JavaScriptSerializer javaScriptSerializer = new JavaScriptSerializer();
Dictionary<string, object> json = (object[])javaScriptSerializer.DeserializeObject(text);

您不需要将其映射到一组类或结构，数组将被转换为 object[]，对象将被转换为 Dictionary。

要查看生成的 Dictionary json 的内容，您可以使用 Visual Studio 检查器或直接访问内容以记住元素的映射方式。

例如访问你只需要的brandLogoUri

(string)json["brandLogoUri"]

要循环resourceSets，即一个数组，您需要执行以下操作

foreach(Dictionary<string,object> key in (Dictionary<string,object>)json["resourceSets"])
{
...do your stuff here...
}

显然，您的代码可读性会降低，但如果将 json 映射到类太困难，或者您想即时进行一些测试，它会很有用

于 2013-10-04T09:34:22.633 回答
2

您可以使用http://json2csharp.com/生成自定义类。将其包含在项目代码中。之后，将相同的 DataContractJsonSerializer 与新的 CustomClass 一起使用。

DataContractJsonSerializer serializer = new DataContractJsonSerializer(typeof(CustomClass));
CustomClass data = serializer.ReadObject(e.Result);

如果你使用 VS2012，你有一个工具：http: //blogs.msdn.com/b/webdev/archive/2012/12/18/paste-json-as-classes-in-asp-net-and-web-tools -2012-2-rc.aspx

于 2013-10-03T17:39:17.197 回答
1

我知道您正在使用 BING 地图，但这里也有一个谷歌解决方案：

Google Map API 请求并使用 C# 解析 DirectionsResponse，将 url 中的 json 更改为 xml，并使用以下代码将结果转换为可用的 C# Generic List Object。

var url = String.Format("http://maps.googleapis.com/maps/api/directions/xml?...");
var result = new System.Net.WebClient().DownloadString(url);
var doc = XDocument.Load(new StringReader(result));

var DirectionsResponse = doc.Elements("DirectionsResponse").Select(l => new
{
    Status = l.Elements("status").Select(q => q.Value).FirstOrDefault(),
    Route = l.Descendants("route").Select(n => new
    {
        Summary = n.Elements("summary").Select(q => q.Value).FirstOrDefault(),
        Leg = n.Elements("leg").ToList().Select(o => new
        {
            Step = o.Elements("step").Select(p => new
            {
                Travel_Mode = p.Elements("travel_mode").Select(q => q.Value).FirstOrDefault(),
                Start_Location = p.Elements("start_location").Select(q => new
                {
                    Lat = q.Elements("lat").Select(r => r.Value).FirstOrDefault(),
                    Lng = q.Elements("lng").Select(r => r.Value).FirstOrDefault()
                }).FirstOrDefault(),
                End_Location = p.Elements("end_location").Select(q => new
                {
                    Lat = q.Elements("lat").Select(r => r.Value).FirstOrDefault(),
                    Lng = q.Elements("lng").Select(r => r.Value).FirstOrDefault()
                }).FirstOrDefault(),
                Polyline = p.Elements("polyline").Select(q => new
                {
                    Points = q.Elements("points").Select(r => r.Value).FirstOrDefault()
                }).FirstOrDefault(),
                Duration = p.Elements("duration").Select(q => new
                {
                    Value = q.Elements("value").Select(r => r.Value).FirstOrDefault(),
                    Text = q.Elements("text").Select(r => r.Value).FirstOrDefault(),
                }).FirstOrDefault(),
                Html_Instructions = p.Elements("html_instructions").Select(q => q.Value).FirstOrDefault(),
                Distance = p.Elements("distance").Select(q => new
                {
                    Value = q.Elements("value").Select(r => r.Value).FirstOrDefault(),
                    Text = q.Elements("text").Select(r => r.Value).FirstOrDefault(),
                }).FirstOrDefault()
            }).ToList(),
            Duration = o.Elements("duration").Select(p => new
            {
                Value = p.Elements("value").Select(q => q.Value).FirstOrDefault(),
                Text = p.Elements("text").Select(q => q.Value).FirstOrDefault()
            }).FirstOrDefault(),
            Distance = o.Elements("distance").Select(p => new
            {
                Value = p.Elements("value").Select(q => q.Value).FirstOrDefault(),
                Text = p.Elements("text").Select(q => q.Value).FirstOrDefault()
            }).FirstOrDefault(),
            Start_Location = o.Elements("start_location").Select(p => new
            {
                Lat = p.Elements("lat").Select(q => q.Value).FirstOrDefault(),
                Lng = p.Elements("lng").Select(q => q.Value).FirstOrDefault()
            }).FirstOrDefault(),
            End_Location = o.Elements("end_location").Select(p => new
            {
                Lat = p.Elements("lat").Select(q => q.Value).FirstOrDefault(),
                Lng = p.Elements("lng").Select(q => q.Value).FirstOrDefault()
            }).FirstOrDefault(),
            Start_Address = o.Elements("start_address").Select(q => q.Value).FirstOrDefault(),
            End_Address = o.Elements("end_address").Select(q => q.Value).FirstOrDefault()
        }).ToList(),
        Copyrights = n.Elements("copyrights").Select(q => q.Value).FirstOrDefault(),
        Overview_polyline = n.Elements("overview_polyline").Select(q => new
        {
            Points = q.Elements("points").Select(r => r.Value).FirstOrDefault()
        }).FirstOrDefault(),
        Waypoint_Index = n.Elements("waypoint_index").Select(o => o.Value).ToList(),
        Bounds = n.Elements("bounds").Select(q => new
        {
            SouthWest = q.Elements("southwest").Select(r => new
            {
                Lat = r.Elements("lat").Select(s => s.Value).FirstOrDefault(),
                Lng = r.Elements("lng").Select(s => s.Value).FirstOrDefault()
            }).FirstOrDefault(),
            NorthEast = q.Elements("northeast").Select(r => new
            {
                Lat = r.Elements("lat").Select(s => s.Value).FirstOrDefault(),
                Lng = r.Elements("lng").Select(s => s.Value).FirstOrDefault()
            }).FirstOrDefault(),
        }).FirstOrDefault()
    }).FirstOrDefault()
}).FirstOrDefault();

我希望这会对某人有所帮助。

于 2013-11-09T22:58:27.523 回答