excel - 如何打开指定其路径的工作簿

Question

Sub openwb()  
    ChDir "E:\sarath\PTMetrics\20131004\D8 L538-L550 16MY"
    Workbooks("D8 L538-L550_16MY_Powertrain Metrics_20131002.xlsm").Open    
End sub

在这里，我Subscript out of range在第 3 行收到一条错误消息。我应该怎么做才能打开指定其路径的工作簿？

Answer 1

Workbooks.open("E:\sarath\PTMetrics\20131004\D8 L538-L550 16MY\D8 L538-L550_16MY_Powertrain Metrics_20131002.xlsm")

或者，以更结构化的方式...

Sub openwb()
    Dim sPath As String, sFile As String
    Dim wb As Workbook

    sPath = "E:\sarath\PTMetrics\20131004\D8 L538-L550 16MY\"
    sFile = sPath & "D8 L538-L550_16MY_Powertrain Metrics_20131002.xlsm"

    Set wb = Workbooks.Open(sFile)
End Sub

Answer 2

您还可以通过提示打开所需的文件，这有助于您从不同的路径和不同的文件中选择文件。

Sub openwb()
Dim wkbk As Workbook
Dim NewFile As Variant

NewFile = Application.GetOpenFilename("microsoft excel files (*.xlsm*), *.xlsm*")

If NewFile <> False Then
Set wkbk = Workbooks.Open(NewFile)
End If
End Sub