1

我有这个来自 sql 查询的数组推送。

Array ( 
[0] => Array ( 
[TICK] => 1015 
    [KD_AIRL] => GA 
    [JUM] => 2834763198 )
[1] => Array ( 
[TICK] => 266 
    [KD_AIRL] => JT 
    [JUM] => 382940267 ) 
[2] => Array ( 
[TICK] => 153 
    [KD_AIRL] => SJY 
    [JUM] => 321328100 ) 
[3] => Array ( 
[TICK] => 672 
    [KD_AIRL] => GA 
    [JUM] => 1131468200.51 ) 
[4] => Array ( 
[TICK] => 239 
    [KD_AIRL] => JT 
    [JUM] => 229913500.25 ) 
[5] => Array ( 
[TICK] => 95 
    [KD_AIRL] => SJY 
    [JUM] => 102319151.00 ) 
)

从上面的数组中，我想按 [KD_AIRL] 分组如下：

Array ( 
[0] => Array ( 
[TICK] => 1687 
    [KD_AIRL] => GA 
    [JUM] => 3966231398 )
[1] => Array ( 
[TICK] => 505 
    [KD_AIRL] => JT 
    [JUM] => 612853767 ) 
[2] => Array ( 
[TICK] => 248 
    [KD_AIRL] => SJY 
    [JUM] => 423647251 ) 
)

然后按 [KD_AIRL] 分组后，我想通过 [JUM] 限制该数组 DESC。所以数组应该是这样的：（例如，我想要限制 2 行）

Array ( 
[0] => Array ( 
[TICK] => 1687 
    [KD_AIRL] => GA 
    [JUM] => 3966231398 )
[1] => Array ( 
[TICK] => 505 
    [KD_AIRL] => JT 
    [JUM] => 612853767 ) 
)

请任何人帮我解决这个问题.. 我应该在 php 代码中做什么？谢谢和最好的问候。

更新 这是我从 sql server 2000 中的所有分支数据库中选择的 php 代码。

<?php
...
...
include "../../../config/dbreportis.php";
// Query for select name branch (NM_BRANCH) and its name database (NM_DATA) in server
$cbranch = mssql_query("SELECT NM_DATA, NM_BRANCH FROM Branch ORDER BY KD_BRANCH ASC");
while ($allbranch = mssql_fetch_array($cbranch)){
// Connect to each branches database (NM_DATA) 
include "../../../config/db.php";
mssql_select_db($allbranch[NM_DATA]);

// Query for selecting all customer and all airline
if (($customer == 'all_customer') AND ($airl == 'all_airline')){
$kueri = "
SELECT     TOP $batas COUNT(d.TICKNO) AS TICK, d.KD_AIRL, SUM(d.FARE + d.TAXIW +   
d.VATVAL + d.TRANSFEE - d.DISVAL) AS JUM
FROM         DInvoiceT d INNER JOIN
HINVOICE h ON h.INVNO = d.INVNO AND h.SRK = d.SRK LEFT OUTER JOIN
Airline a ON a.KD_AIRL = d.KD_AIRL 
WHERE     (h.INVDATE >= '$from') AND (h.INVDATE <= '$to') AND (h.INOUT = '$inout')  
AND (h.SRK = 'TX') AND (h.CPRINT = 'Y') AND (h.SVD = '')
GROUP BY d.KD_AIRL
ORDER BY JUM DESC";
}
// Query for selecting all customer but specific airline
elseif (($customer == 'all_customer') AND ($airl != 'all_airline')){
$kueri = "
SELECT     TOP $batas COUNT(d.TICKNO) AS TICK, d.KD_AIRL, SUM(d.FARE + d.TAXIW +   
d.VATVAL + d.TRANSFEE - d.DISVAL) AS JUM
FROM         DInvoiceT d INNER JOIN
HINVOICE h ON h.INVNO = d.INVNO AND h.SRK = d.SRK LEFT OUTER JOIN
Airline a ON a.KD_AIRL = d.KD_AIRL 
WHERE     (h.INVDATE >= '$from') AND (h.INVDATE <= '$to') AND (h.INOUT = '$inout') AND 
(h.SRK = 'TX')  AND (d.KD_AIRL = '$airl') AND (h.CPRINT = 'Y') AND (h.SVD = '')
GROUP BY d.KD_AIRL
ORDER BY JUM DESC";
}
$ticket= 0;
$sumvalue = 0;
$data = mssql_query($kueri);

while ($r = mssql_fetch_assoc($data)){
$nm_airl = mssql_query("SELECT NM_AIRL FROM Airline WHERE KD_AIRL = '$r[KD_AIRL]'");
$do_airl = mssql_fetch_array($nm_airl);
if ($do_airl['NM_AIRL'] == ''){
$nama_airline = '';
}elseif ($do_airl['NM_AIRL'] != ''){
$nama_airline = $do_airl['NM_AIRL'];
}
$do_nama_airline = "$r[KD_AIRL]-$nama_airline";
echo "<tr>
<td align='left'>$no</td>
<td align='left'>$do_nama_airline</td>
<td align='right'>$r[TICK]</td>
<td align='right'>".number_format($r[JUM], 2 , '.' , ',' );
echo "</td>
</tr>";
$ticket += $r['TICK'];
$sumvalue += $r['JUM'];
$ticket_all += $r['TICK'];
$sumvalue_all += $r['JUM'];
$no++;
} 
if ($sumvalue > 0){
echo "<tr>
<td colspan='2' align='right'>Total $airline1 :</td>
<td align='right'>".number_format($ticket, 2 , '.' , ',' );
echo "</td>
<td align='right'>".number_format($sumvalue, 2 , '.' , ',' );
echo "</td>
</tr>";
}
}
echo "<tr>
<td colspan='2' align='right'>Grand Total</td>
<td align='right'>".number_format($ticket_all, 2 , '.' , ',' );
echo "</td>
<td align='right'>".number_format($sumvalue_all, 2 , '.' , ',' );
echo "</td>
</tr>";
echo "</table>";
mssql_close();
?>

通过上面的代码，如果我有 20 个分支并且想要显示前 20 个结果，脚本将给出 20*20 = 400 行的结果。但我想要的是一份报告，它显示 20 行并且还按 [KD_AIRL] 分组并按 [JUM] 排序 DESC。

因此，我尝试将上面脚本中的查询结果推送到新数组，然后按 [KD_AIRL] 对其进行分组，并按 [JUM] 对 DESC 进行排序，最后将其限制为 20（例如）。

注意 当我使用下面的解决方案脚本时，并非所有 [KD_AIRL] 分组（eq [GA] 再次重复）：此结果取自 sql server 中的所有分支数据库。

Array
(
    [GA ] => Array
    (
        [TICK] => 1863
        [KD_AIRL] => GA 
        [JUM] => 3906190760.99
    )

    [JT ] => Array
    (
        [TICK] => 787
        [KD_AIRL] => JT 
        [JUM] => 723166135.39
    )

    [SJY] => Array
    (
        [TICK] => 138
        [KD_AIRL] => SJY
        [JUM] => 164732319
    )

    [GAC] => Array
    (
        [TICK] => 101
        [KD_AIRL] => GAC
        [JUM] => 145669200
    )

    [GA] => Array
    (
        [TICK] => 52
        [KD_AIRL] => GA
        [JUM] => 60380240
    )

    [KP ] => Array
    (
        [TICK] => 29
        [KD_AIRL] => KP 
        [JUM] => 31069700
    )

    [JT] => Array
    (
        [TICK] => 41
        [KD_AIRL] => JT
        [JUM] => 31058000
    )

    [QG ] => Array
    (
        [TICK] => 46
        [KD_AIRL] => QG 
        [JUM] => 30951350.57
    )

    [ID ] => Array
    (
        [TICK] => 36
        [KD_AIRL] => ID 
        [JUM] => 22508000
    )

    [MZ ] => Array
    (
        [TICK] => 26
        [KD_AIRL] => MZ 
        [JUM] => 22081400
    )

    [AK ] => Array
    (
        [TICK] => 23
        [KD_AIRL] => AK 
        [JUM] => 21385468
    )

    [TGN] => Array
    (
        [TICK] => 26
        [KD_AIRL] => TGN
        [JUM] => 20125400
    )

    [QZ ] => Array
    (
        [TICK] => 17
        [KD_AIRL] => QZ 
        [JUM] => 12856500
    )

    [QZ] => Array
    (
        [TICK] => 11
        [KD_AIRL] => QZ
        [JUM] => 8810000
    )

    [IW ] => Array
    (
        [TICK] => 4
        [KD_AIRL] => IW 
        [JUM] => 6965000
    )

    [RI ] => Array
    (
        [TICK] => 6
        [KD_AIRL] => RI 
        [JUM] => 6494800
    )

    [IL ] => Array
    (
        [TICK] => 7
        [KD_AIRL] => IL 
        [JUM] => 5572000
    )

    [SI ] => Array
    (
        [TICK] => 6
        [KD_AIRL] => SI 
        [JUM] => 5260800
    )

    [6N ] => Array
    (
        [TICK] => 6
        [KD_AIRL] => 6N 
        [JUM] => 4187520
    )

    [MV ] => Array
    (
        [TICK] => 2
        [KD_AIRL] => MV 
        [JUM] => 3225735
    )

)

我需要的是所有 [KD_AIRL] 分组和排序的 DESC 并最终限制为 20 行（例如）。如果有一种方法可以通过 sql 查询而不是 php 代码来获取我想要的报告，那就太好了。请给我这个案例的解决方案。非常感谢。

4

3 回答 3

1

试试这个代码

<?php
// Your mysql result
$myArray = Array ( 0 => Array ('TICK' => 1015, 'KD_AIRL' => 'GA','JUM' => 2834763198 ),
                 1 => Array ('TICK' => 266 ,'KD_AIRL' => 'JT','JUM' => 382940267 ) ,
                 2 => Array ('TICK' => 153 ,'KD_AIRL' => 'SJY','JUM' => 321328100 ),
                 3 => Array ('TICK' => 672,'KD_AIRL' => 'GA','JUM' => 1131468200.00 ),
                 4 => Array ('TICK' => 239,'KD_AIRL' => 'JT','JUM' => 229913500.00 ) ,
                 5 => Array ('TICK' => 95,'KD_AIRL' => 'SJY','JUM' => 102319151.00 ) );

// Some Variables are declare here               
$sumArray = array();
$getAllData = array();
$final_result = array();

// *********** Some Function **************************
// Sum, your array
function sum_array($myArray){
    $return = array();
    foreach ($myArray as $k=>$subsumArray) {
      foreach ($subsumArray as $id=>$value) {

        if($id == 'KD_AIRL'){
            $return[$id] =$value;
        }else{
            $return[$id]+=$value;
        }
      }
    }
return $return;      

}
//////////////////////
function cmp($a, $b) {

    $a = $a['JUM'];
    $b = $b['JUM'];

    if ($a == $b) {
        return 0;
    }
    return ($a < $b) ? 1 : -1;
}
//***********************************************************

foreach ($myArray as $k=>$subArray) {
    $getAllData[$subArray['KD_AIRL']][] = $subArray;            
}

// Replace below code with old new(changes baove code)
$new_array = array();
foreach ($getAllData as $key => $Data_val){

    if (!array_key_exists($key, $final_result)) {
       $final_result[$key] = sum_array($Data_val);
       $new_array[] =  sum_array($Data_val);
    }   
}


uasort($new_array, 'cmp');


// Set limit
$limit = 2;
$oupout=array_slice($new_array,0,$limit);

echo "<pre>";
print_r($oupout);
echo "</pre>";
exit;

?>
于 2013-10-04T07:01:33.647 回答
0

我认为这个问题可以通过 SQL 中的 groupby 和 limit 来解决。

但是......如果你真的想要这里的 php 代码，那就是它。

$array = Array(); // YOUR DATA

// get `KD_AIRL` as list
$result = array();
foreach($array as $item){
    if(!in_array($item['KD_AIRL'], $result)){
        $result[$item['KD_AIRL']] = array(
            'TICK' => 0,
            'KD_AIRL' => $item['KD_AIRL'],
            'JMP' => 0
        );
      }
}

// group TRICK and JMP
foreach($array as $item){
    if(isset($result[$item['KD_AIRL']])){
        $result[$item['KD_AIRL']]['TICK'] += $item['TICK'];
        $result[$item['KD_AIRL']]['JMP'] += $item['JMP'];
    }
}

// sort by JMP DESC
function cmp($a, $b) {

    $a = $a['JMP'];
    $b = $b['JMP'];

    if ($a == $b) {
        return 0;
    }
    return ($a < $b) ? 1 : -1;
}
uasort($array, 'cmp');

// get by limit
$limit = 2;
array_slice($array, $limit-1);
于 2013-10-03T05:25:22.740 回答
0

通过 Mysql 函数 GroupBy、Sum 和 Limit 轻松解决问题，

你能告诉我你的表结构和你的sql查询吗？

<?php
// Your mysql result
$myArray = Array ( 0 => Array ('TICK' => 1015, 'KD_AIRL' => 'GA','JUM' => 2834763198 ),
                 1 => Array ('TICK' => 266 ,'KD_AIRL' => 'JT','JUM' => 382940267 ) ,
                 2 => Array ('TICK' => 153 ,'KD_AIRL' => 'SJY','JUM' => 321328100 ),
                 3 => Array ('TICK' => 672,'KD_AIRL' => 'GA','JUM' => 1131468200.00 ),
                 4 => Array ('TICK' => 239,'KD_AIRL' => 'JT','JUM' => 229913500.00 ) ,
                 5 => Array ('TICK' => 95,'KD_AIRL' => 'SJY','JUM' => 102319151.00 ) );

// Some Variables are declare here               
$sumArray = array();
$getAllData = array();
$final_result = array();

// *********** Some Function **************************
// Sum, your array
function sum_array($myArray){
    $return = array();
    foreach ($myArray as $k=>$subsumArray) {
      foreach ($subsumArray as $id=>$value) {

        if($id == 'KD_AIRL'){
            $return[$id] =$value;
        }else{
            $return[$id]+=$value;
        }
      }
    }
return $return;      

}
//////////////////////
function cmp($a, $b) {

    $a = $a['JUM'];
    $b = $b['JUM'];

    if ($a == $b) {
        return 0;
    }
    return ($a < $b) ? 1 : -1;
}
//***********************************************************

foreach ($myArray as $k=>$subArray) {
    $getAllData[$subArray['KD_AIRL']][] = $subArray;            
}


foreach ($getAllData as $key => $Data_val){

    if (!array_key_exists($key, $final_result)) {
       $final_result[$key] = sum_array($Data_val);  
    }   
}

uasort($final_result, 'cmp');

// Set limit
$limit = 2;
$oupout=array_slice($final_result,0,$limit);

echo "<pre>";
print_r($oupout);
echo "</pre>";
exit;

?>

你的输出

<pre>Array
(
    [GA] => Array
        (
            [TICK] => 1687
            [KD_AIRL] => GA
            [JUM] => 3966231398
        )

    [JT] => Array
        (
            [TICK] => 505
            [KD_AIRL] => JT
            [JUM] => 612853767
        )

)
</pre>
于 2013-10-03T08:47:44.027 回答