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我正在尝试将以下代码实现到我自己的中。

这是我要实现的代码。这是为了获得有关系的排名，并且在关系之后排名是不连续的。

SET @rnk=0;
SET @rank=0;
SET @curscore=0;

SELECT score,ID,rank FROM (

    SELECT AA.*,BB.ID,
    (@rnk:=@rnk+1) rnk,
    (@rank:=IF(@curscore=score,@rank,@rnk)) rank,
    (@curscore:=score) newscore
    FROM (

        SELECT * FROM (

            SELECT COUNT(1) scorecount,score
            FROM scores GROUP BY score

        ) AAA
        ORDER BY score DESC

    ) AA LEFT JOIN scores BB USING (score)

) A;

这是我从中获取代码的链接。这是第二个答案。

https://dba.stackexchange.com/questions/13703/get-the-rank-of-a-user-in-a-score-table

我的代码如下。我用“totalPoints”交换了“分数”。这是我得到的。

我在代码的两部分遇到问题。

这一行，BB.ID 部分。

SELECT AA.*, BB.ID,

还有这条线。

) AA LEFT JOIN scores BB USING (score)

我知道代码在做什么我只是不知道如何用我的代码和表格替换这些部分以使它们工作。

SET @rnk=0;
SET @rank=0;
SET @curscore=0;

SELECT AA.*, BB.ID,
(@rnk:=@rnk+1) rnk,
(@rank:=IF(@curscore=totalPoints,@rank,@rnk)) rank,
(@curscore:=totalPoints) newPoints
FROM (

    SELECT * FROM (

        SELECT COUNT(1) scorecount, totalPoints FROM (

            #----------start of my code

            SELECT *, (totalWins+(totalPushs*.5)) AS totalPoints, totalWins+totalLost+totalPushs AS totalBets FROM (

                SELECT *, SUM(win) AS totalWins, SUM(lost) AS totalLost, SUM(push) AS totalPushs FROM (

                    SELECT *, (finalResult = 'Winner') AS win, (finalResult = 'Loser') AS lost, (finalResult = 'Push') AS push FROM (

                        SELECT nflp_users.userID, userName, avatar, teamColor,
                        IF (pickID=visitorID, visitorResult, homeResult) AS finalResult
                        FROM nflp_users
                        JOIN nflp_picks
                        ON nflp_users.userID = nflp_picks.userID
                        JOIN nflp_schedule
                        ON nflp_picks.gameID = nflp_schedule.gameID
                    ) x

                ) x
                GROUP BY userID

            ) x

            #----------end of my code

        ) x GROUP BY totalPoints

    ) AAA
    ORDER BY totalPoints DESC

) AA LEFT JOIN scores BB USING (score)
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