您好我正在尝试从 url 解析 XML 文件,我的 NodeList 包含值,但每个节点的 getNodeValue 都返回 null。有谁能够帮我?
这是我解析xml的方法。
public ArrayList xmloku(String url) {
ArrayList xmllistesi = new ArrayList();
try {
URL xmlyolu = new URL(url);
DocumentBuilderFactory dFactory = DocumentBuilderFactory
.newInstance();
DocumentBuilder dBuilder = dFactory.newDocumentBuilder();
Document document = dBuilder.parse(new InputSource(xmlyolu
.openStream()));
document.getDocumentElement().normalize();
NodeList nodeListCountry = document
.getElementsByTagName("karikatur");
for (int i = konum; i < nodeListCountry.getLength(); i++) {
Node node = nodeListCountry.item(i);
Element elementMain = (Element) node;
xmllistesi.add(elementMain.getNodeValue());
}