3

我正在尝试开发一个查询来确定一个人在一个季度内每天服用的药物量。在某些日子，没有处方药，对于其他日子，可能会有重叠，我需要一个总量（意思是一天中每种药物的强度）。药物的数量、强度、日用品等可能会有所不同。这里有一些数据：

create table #MemberInfo 
(ProgramName varchar(255), 
DateFilled datetime, 
DaySupply integer, 
MemberID varchar(255), 
Strength integer, 
Tradename varchar(255));

insert into #MemberInfo
Values ('InsureCo', '20130612', 30, 'MEM001', 10, 'Sedative')
, ('InsureCo', '20130429', 30, 'MEM001', 20, 'Sedative')
, ('InsureCo', '20130401', 30, 'MEM001', 20, 'Sedative')
, ('InsureCo', '20130529', 30, 'MEM001', 30, 'Sedative')

我真的不知道在一个季度中将某一天服用的药物量加起来最好的方法是什么。如果可以的话，我想避免使用游标。我正在考虑创建一个包含所有天数的临时表，然后以某种方式将这些日期加入到每天服用药物（即，DateFilled + 之后的每一天直到 DaySupply）。一旦我知道了一个季度内每种药物的日期和数量，我就可以按天分组并获得每天的总和。我还需要能够获得超过四分之一的平均金额。

其他要求：

  1. 我有一个开始日期和天数。我想为每个成员每天有一个处方创建一行（并为他们的所有处方做同样的事情）。然后我会总结每天所有药物的强度。如果有帮助的话，所有的药物都将属于同一类别，强度将是等效剂量，这意味着我可以总结它们。

  2. 对于报告，我需要能够计算金额大于某个截止值（比如说 100）的连续天数。这就是为什么我试图每天获得金额。

    Desired output

MemberID    Date        SumStrength
MEM001     2013-04-29  40
MEM001     2013-04-30  40
MEM001     2013-05-01  20
ETC FOR EVERY DAY FOR THIS MEMBER

MEM002     2013-04-01  60
MEM002     2013-04-02  40
ETC FOR EVERY DAY FOR THIS MEMBER
4

3 回答 3

1

我认为只是一个简单的组。

create table #MemberInfo 
(ProgramName varchar(255), 
DateFilled datetime, 
DaySupply integer, 
MemberID varchar(255), 
Strength integer, 
Tradename varchar(255));

insert into #MemberInfo
Values ('InsureCo', '20130612', 30, 'MEM001', 10, 'Sedative')
, ('InsureCo', '20130429', 30, 'MEM001', 20, 'Sedative')
, ('InsureCo', '20130429', 30, 'MEM002', 25, 'Sedative')
, ('InsureCo', '20130515', 30, 'MEM002', 25, 'Sedative')
, ('InsureCo', '20130401', 30, 'MEM001', 20, 'Sedative')
, ('InsureCo', '20130529', 30, 'MEM001', 30, 'Sedative')
, ('InsureCo', '20130529', 30, 'MEM003', 35, 'Sedative')
, ('InsureCo', '20130529', 30, 'MEM003', 45, 'Sedative')

select memberid,datefilled,SUM(strength) as [Strength sum]
from #MemberInfo
where memberid = 'MEM003' -- or whatever, could be a parameter
group by memberid,DateFilled

order by Memberid,DateFilled

drop table #MemberInfo
于 2013-10-02T20:09:54.750 回答
1

这是一个示例，说明如何使用 a 构建日历CTE并使用OVER(PARTION BY)

询问：

-- Declare a Start and End Date required to build a calendar
DECLARE @StartDate DATETIME = '2013-01-01'
DECLARE @EndDate   DATETIME = '2015-01-01'

-- Build out a Day/Quarter Calendar
;WITH Calendar ([Date], [Quarter]) AS (
    SELECT @StartDate, 1
    UNION ALL
    SELECT [Date] + 1, (DATEDIFF(m, @StartDate, [Date] + 1) / 3) + 1
    FROM Calendar 
    WHERE [Date] + 1 < @EndDate
)

-- Build Result Set
SELECT  ProgramName, 
        DateFilled, 
        DaySupply, 
        MemberID, 
        Strength,
        Quarter,
        SUM(Strength) OVER(PARTITION BY ProgramName, DaySupply, MemberID, Quarter) AS QuarterlyTotal,
        AVG(Strength) OVER(PARTITION BY ProgramName, DaySupply, MemberID, Quarter) AS QuarterlyAverage
FROM #MemberInfo MI
JOIN Calendar C ON MI.DateFilled = C.[Date]
ORDER BY MemberID, DateFilled
OPTION (MAXRECURSION 0)

测试数据：

create table #MemberInfo 
(ProgramName varchar(255), 
DateFilled datetime, 
DaySupply integer, 
MemberID varchar(255), 
Strength integer, 
Tradename varchar(255));

INSERT INTO #MemberInfo
Values
    --MEM001
    --Q1
     ('InsureCo', '20130112', 30, 'MEM001', 10, 'Sedative')
    ,('InsureCo', '20130129', 30, 'MEM001', 20, 'Sedative')
    ,('InsureCo', '20130401', 30, 'MEM001', 20, 'Sedative')
    --Q2
    ,('InsureCo', '20130529', 30, 'MEM001', 30, 'Sedative')
    ,('InsureCo', '20130429', 30, 'MEM001', 20, 'Sedative')
    ,('InsureCo', '20130401', 30, 'MEM001', 20, 'Sedative')
    --Q3
    ,('InsureCo', '20130829', 30, 'MEM001', 30, 'Sedative')

    --MEM002
    --Q1
    ,('InsureCo', '20130112', 30, 'MEM002', 10, 'Sedative')
    ,('InsureCo', '20130129', 30, 'MEM002', 20, 'Sedative')
    ,('InsureCo', '20130401', 30, 'MEM002', 20, 'Sedative')
    --Q2
    ,('InsureCo', '20130529', 30, 'MEM002', 30, 'Sedative')
    ,('InsureCo', '20130429', 30, 'MEM002', 20, 'Sedative')
    ,('InsureCo', '20130401', 30, 'MEM002', 20, 'Sedative')
    --Q3
    ,('InsureCo', '20130829', 30, 'MEM002', 30, 'Sedative')
    --Q4
    ,('InsureCo', '20131129', 30, 'MEM002', 30, 'Sedative')

结果：

ProgramName DateFilled  DaySupply   MemberID    Strength    Quarter QuarterlyTotal  QuarterlyAverage
InsureCo    2013-01-12  30          MEM001      10          1       30              15
InsureCo    2013-01-29  30          MEM001      20          1       30              15
InsureCo    2013-04-01  30          MEM001      20          2       90              22
InsureCo    2013-04-01  30          MEM001      20          2       90              22
InsureCo    2013-04-29  30          MEM001      20          2       90              22
InsureCo    2013-05-29  30          MEM001      30          2       90              22
InsureCo    2013-08-29  30          MEM001      30          3       30              30
InsureCo    2013-01-12  30          MEM002      10          1       30              15
InsureCo    2013-01-29  30          MEM002      20          1       30              15
InsureCo    2013-04-01  30          MEM002      20          2       90              22
InsureCo    2013-04-01  30          MEM002      20          2       90              22
InsureCo    2013-04-29  30          MEM002      20          2       90              22
InsureCo    2013-05-29  30          MEM002      30          2       90              22
InsureCo    2013-08-29  30          MEM002      30          3       30              30
InsureCo    2013-11-29  30          MEM002      30          4       30              30
于 2013-10-02T20:17:22.817 回答
0

今晚我已经玩了一些，我离得更近了：

一些数据：

create TABLE dateranges (drug VARCHAR(5), date_begin DATETIME, numdays integer,strength        integer)
INSERT into dateranges values ('DrugA', '2010-01-01', 5, 10);
INSERT into dateranges values ('DrugB', '2008-02-27', 10, 20);
INSERT into dateranges values ('DrugC', '2010-04-26', 3, 20);
INSERT into dateranges values ('DrugD', '2000-02-01', 5, 30);

CTE：

WITH cte (id, d, s)
     AS (SELECT tbl.drug AS id
                ,tbl.date_begin AS d
                ,tbl.strength AS s
           FROM dateranges tbl
          WHERE DATEDIFF(DAY, tbl.date_begin, tbl.date_begin+numdays-1) <= 100
         UNION ALL
         SELECT tbl.drug AS id
                ,DATEADD(DAY, 1, cte.d) AS d
                ,tbl.strength as s
           FROM cte
                INNER JOIN dateranges tbl
                  ON cte.id = tbl.drug
          WHERE cte.d < tbl.date_begin+numdays-1)
SELECT id AS drug
       ,d AS dates
       ,s AS strength
  FROM cte
 ORDER BY id, d, s

结果：

DRUG    DATES   STRENGTH
DrugA   January, 01 2010 00:00:00+0000  10
DrugA   January, 02 2010 00:00:00+0000  10
DrugA   January, 03 2010 00:00:00+0000  10
DrugA   January, 04 2010 00:00:00+0000  10
DrugA   January, 05 2010 00:00:00+0000  10
DrugB   February, 27 2008 00:00:00+0000 20
DrugB   February, 28 2008 00:00:00+0000 20
DrugB   February, 29 2008 00:00:00+0000 20
DrugB   March, 01 2008 00:00:00+0000    20
DrugB   March, 02 2008 00:00:00+0000    20
DrugB   March, 03 2008 00:00:00+0000    20
DrugB   March, 04 2008 00:00:00+0000    20
DrugB   March, 05 2008 00:00:00+0000    20
DrugB   March, 06 2008 00:00:00+0000    20
DrugB   March, 07 2008 00:00:00+0000    20
DrugC   April, 26 2010 00:00:00+0000    20
DrugC   April, 27 2010 00:00:00+0000    20
DrugC   April, 28 2010 00:00:00+0000    20
DrugD   February, 01 2000 00:00:00+0000 30
DrugD   February, 02 2000 00:00:00+0000 30
DrugD   February, 03 2000 00:00:00+0000 30
DrugD   February, 04 2000 00:00:00+0000 30
DrugD   February, 05 2000 00:00:00+0000 30

从这里开始，我计划按药物、日期、强度（总和强度）进行分组。我应该能够将这些结果扔到临时表中，然后计算超过我提到的阈值的天数。

于 2013-10-03T01:52:14.077 回答