我正在尝试使用 Paul Carter 博士的 pcasm 书来学习组装：http ://www.drpaulcarter.com/pcasm/
作者没有打包 Mac OS X 示例，然后我从 linux 源开始使用。这是第一个示例，它使用了他的库 asm_io。
运行时出现分段错误。为什么？在mac中运行需要改变什么？
我想如果你知道 asm，也许你可以告诉我发生了什么。
这是来源。
asm_io.asm：
;
; file: asm_io.asm
; Assembly I/O routines
; To assemble for DJGPP
; nasm -f coff -d COFF_TYPE asm_io.asm
; To assemble for Borland C++ 5.x
; nasm -f obj -d OBJ_TYPE asm_io.asm
; To assemble for Microsoft Visual Studio
; nasm -f win32 -d COFF_TYPE asm_io.asm
; To assemble for Linux
; nasm -f elf -d ELF_TYPE asm_io.asm
; To assemble for Watcom
; nasm -f obj -d OBJ_TYPE -d WATCOM asm_io.asm
; IMPORTANT NOTES FOR WATCOM
; The Watcom compiler's C library does not use the
; standard C calling convention. For example, the
; putchar() function gets its argument from the
; the value of EAX, not the stack.
%define NL 10
%define CF_MASK 00000001h
%define PF_MASK 00000004h
%define AF_MASK 00000010h
%define ZF_MASK 00000040h
%define SF_MASK 00000080h
%define DF_MASK 00000400h
%define OF_MASK 00000800h
;
; Linux C doesn't put underscores on labels
;
%ifdef ELF_TYPE
%define _scanf scanf
%define _printf printf
%define _getchar getchar
%define _putchar putchar
%endif
;
; Watcom puts underscores at end of label
;
%ifdef WATCOM
%define _scanf scanf_
%define _printf printf_
%define _getchar getchar_
%define _putchar putchar_
%endif
%ifdef OBJ_TYPE
segment .data public align=4 class=data use32
%else
segment .data
%endif
int_format db "%i", 0
string_format db "%s", 0
reg_format db "Register Dump # %d", NL
db "EAX = %.8X EBX = %.8X ECX = %.8X EDX = %.8X", NL
db "ESI = %.8X EDI = %.8X EBP = %.8X ESP = %.8X", NL
db "EIP = %.8X FLAGS = %.4X %s %s %s %s %s %s %s", NL
db 0
carry_flag db "CF", 0
zero_flag db "ZF", 0
sign_flag db "SF", 0
parity_flag db "PF", 0
overflow_flag db "OF", 0
dir_flag db "DF", 0
aux_carry_flag db "AF", 0
unset_flag db " ", 0
mem_format1 db "Memory Dump # %d Address = %.8X", NL, 0
mem_format2 db "%.8X ", 0
mem_format3 db "%.2X ", 0
stack_format db "Stack Dump # %d", NL
db "EBP = %.8X ESP = %.8X", NL, 0
stack_line_format db "%+4d %.8X %.8X", NL, 0
math_format1 db "Math Coprocessor Dump # %d Control Word = %.4X"
db " Status Word = %.4X", NL, 0
valid_st_format db "ST%d: %.10g", NL, 0
invalid_st_format db "ST%d: Invalid ST", NL, 0
empty_st_format db "ST%d: Empty", NL, 0
;
; code is put in the _TEXT segment
;
%ifdef OBJ_TYPE
segment text public align=1 class=code use32
%else
segment .text
%endif
global read_int, print_int, print_string, read_char
global print_char, print_nl, sub_dump_regs, sub_dump_mem
global sub_dump_math, sub_dump_stack
extern _scanf, _printf, _getchar, _putchar
read_int:
enter 4,0
pusha
pushf
lea eax, [ebp-4]
push eax
push dword int_format
call _scanf
pop ecx
pop ecx
popf
popa
mov eax, [ebp-4]
leave
ret
print_int:
enter 0,0
pusha
pushf
push eax
push dword int_format
call _printf
pop ecx
pop ecx
popf
popa
leave
ret
print_string:
enter 0,0
pusha
pushf
push eax
push dword string_format
call _printf
pop ecx
pop ecx
popf
popa
leave
ret
read_char:
enter 4,0
pusha
pushf
call _getchar
mov [ebp-4], eax
popf
popa
mov eax, [ebp-4]
leave
ret
print_char:
enter 0,0
pusha
pushf
%ifndef WATCOM
push eax
%endif
call _putchar
%ifndef WATCOM
pop ecx
%endif
popf
popa
leave
ret
print_nl:
enter 0,0
pusha
pushf
%ifdef WATCOM
mov eax, 10 ; WATCOM doesn't use the stack here
%else
push dword 10 ; 10 == ASCII code for \n
%endif
call _putchar
%ifndef WATCOM
pop ecx
%endif
popf
popa
leave
ret
sub_dump_regs:
enter 4,0
pusha
pushf
mov eax, [esp] ; read FLAGS back off stack
mov [ebp-4], eax ; save flags
;
; show which FLAGS are set
;
test eax, CF_MASK
jz cf_off
mov eax, carry_flag
jmp short push_cf
cf_off:
mov eax, unset_flag
push_cf:
push eax
test dword [ebp-4], PF_MASK
jz pf_off
mov eax, parity_flag
jmp short push_pf
pf_off:
mov eax, unset_flag
push_pf:
push eax
test dword [ebp-4], AF_MASK
jz af_off
mov eax, aux_carry_flag
jmp short push_af
af_off:
mov eax, unset_flag
push_af:
push eax
test dword [ebp-4], ZF_MASK
jz zf_off
mov eax, zero_flag
jmp short push_zf
zf_off:
mov eax, unset_flag
push_zf:
push eax
test dword [ebp-4], SF_MASK
jz sf_off
mov eax, sign_flag
jmp short push_sf
sf_off:
mov eax, unset_flag
push_sf:
push eax
test dword [ebp-4], DF_MASK
jz df_off
mov eax, dir_flag
jmp short push_df
df_off:
mov eax, unset_flag
push_df:
push eax
test dword [ebp-4], OF_MASK
jz of_off
mov eax, overflow_flag
jmp short push_of
of_off:
mov eax, unset_flag
push_of:
push eax
push dword [ebp-4] ; FLAGS
mov eax, [ebp+4]
sub eax, 10 ; EIP on stack is 10 bytes ahead of orig
push eax ; EIP
lea eax, [ebp+12]
push eax ; original ESP
push dword [ebp] ; original EBP
push edi
push esi
push edx
push ecx
push ebx
push dword [ebp-8] ; original EAX
push dword [ebp+8] ; # of dump
push dword reg_format
call _printf
add esp, 76
popf
popa
leave
ret 4
sub_dump_stack:
enter 0,0
pusha
pushf
lea eax, [ebp+20]
push eax ; original ESP
push dword [ebp] ; original EBP
push dword [ebp+8] ; # of dump
push dword stack_format
call _printf
add esp, 16
mov ebx, [ebp] ; ebx = original ebp
mov eax, [ebp+16] ; eax = # dwords above ebp
shl eax, 2 ; eax *= 4
add ebx, eax ; ebx = & highest dword in stack to display
mov edx, [ebp+16]
mov ecx, edx
add ecx, [ebp+12]
inc ecx ; ecx = # of dwords to display
stack_line_loop:
push edx
push ecx ; save ecx & edx
push dword [ebx] ; value on stack
push ebx ; address of value on stack
mov eax, edx
sal eax, 2 ; eax = 4*edx
push eax ; offset from ebp
push dword stack_line_format
call _printf
add esp, 16
pop ecx
pop edx
sub ebx, 4
dec edx
loop stack_line_loop
popf
popa
leave
ret 12
sub_dump_mem:
enter 0,0
pusha
pushf
push dword [ebp+12]
push dword [ebp+16]
push dword mem_format1
call _printf
add esp, 12
mov esi, [ebp+12] ; address
and esi, 0FFFFFFF0h ; move to start of paragraph
mov ecx, [ebp+8]
inc ecx
mem_outer_loop:
push ecx
push esi
push dword mem_format2
call _printf
add esp, 8
xor ebx, ebx
mem_hex_loop:
xor eax, eax
mov al, [esi + ebx]
push eax
push dword mem_format3
call _printf
add esp, 8
inc ebx
cmp ebx, 16
jl mem_hex_loop
mov eax, '"'
call print_char
xor ebx, ebx
mem_char_loop:
xor eax, eax
mov al, [esi+ebx]
cmp al, 32
jl non_printable
cmp al, 126
jg non_printable
jmp short mem_char_loop_continue
non_printable:
mov eax, '?'
mem_char_loop_continue:
call print_char
inc ebx
cmp ebx, 16
jl mem_char_loop
mov eax, '"'
call print_char
call print_nl
add esi, 16
pop ecx
loop mem_outer_loop
popf
popa
leave
ret 12
; function sub_dump_math
; prints out state of math coprocessor without modifying the coprocessor
; or regular processor state
; Parameters:
; dump number - dword at [ebp+8]
; Local variables:
; ebp-108 start of fsave buffer
; ebp-116 temp double
; Notes: This procedure uses the Pascal convention.
; fsave buffer structure:
; ebp-108 control word
; ebp-104 status word
; ebp-100 tag word
; ebp-80 ST0
; ebp-70 ST1
; ebp-60 ST2 ...
; ebp-10 ST7
;
sub_dump_math:
enter 116,0
pusha
pushf
fsave [ebp-108] ; save coprocessor state to memory
mov eax, [ebp-104] ; status word
and eax, 0FFFFh
push eax
mov eax, [ebp-108] ; control word
and eax, 0FFFFh
push eax
push dword [ebp+8]
push dword math_format1
call _printf
add esp, 16
;
; rotate tag word so that tags in same order as numbers are
; in the stack
;
mov cx, [ebp-104] ; ax = status word
shr cx, 11
and cx, 7 ; cl = physical state of number on stack top
mov bx, [ebp-100] ; bx = tag word
shl cl,1 ; cl *= 2
ror bx, cl ; move top of stack tag to lowest bits
mov edi, 0 ; edi = stack number of number
lea esi, [ebp-80] ; esi = address of ST0
mov ecx, 8 ; ecx = loop counter
tag_loop:
push ecx
mov ax, 3
and ax, bx ; ax = current tag
or ax, ax ; 00 -> valid number
je valid_st
cmp ax, 1 ; 01 -> zero
je zero_st
cmp ax, 2 ; 10 -> invalid number
je invalid_st
push edi ; 11 -> empty
push dword empty_st_format
call _printf
add esp, 8
jmp short cont_tag_loop
zero_st:
fldz
jmp short print_real
valid_st:
fld tword [esi]
print_real:
fstp qword [ebp-116]
push dword [ebp-112]
push dword [ebp-116]
push edi
push dword valid_st_format
call _printf
add esp, 16
jmp short cont_tag_loop
invalid_st:
push edi
push dword invalid_st_format
call _printf
add esp, 8
cont_tag_loop:
ror bx, 2 ; mov next tag into lowest bits
inc edi
add esi, 10 ; mov to next number on stack
pop ecx
loop tag_loop
frstor [ebp-108] ; restore coprocessor state
popf
popa
leave
ret 4
asm_io.inc：
extern read_int, print_int, print_string
extern read_char, print_char, print_nl
extern sub_dump_regs, sub_dump_mem, sub_dump_math, sub_dump_stack
%macro dump_regs 1
push dword %1
call sub_dump_regs
%endmacro
;
; usage: dump_mem label, start-address, # paragraphs
%macro dump_mem 3
push dword %1
push dword %2
push dword %3
call sub_dump_mem
%endmacro
%macro dump_math 1
push dword %1
call sub_dump_math
%endmacro
%macro dump_stack 3
push dword %3
push dword %2
push dword %1
call sub_dump_stack
%endmacro
第一个.asm
;
; file: first.asm
; First assembly program. This program asks for two integers as
; input and prints out their sum.
;
; To create executable:
; Using djgpp:
; nasm -f coff first.asm
; gcc -o first first.o driver.c asm_io.o
;
; Using Linux and gcc:
; nasm -f elf first.asm
; gcc -o first first.o driver.c asm_io.o
;
; Using Borland C/C++
; nasm -f obj first.asm
; bcc32 first.obj driver.c asm_io.obj
;
; Using MS C/C++
; nasm -f win32 first.asm
; cl first.obj driver.c asm_io.obj
;
; Using Open Watcom
; nasm -f obj first.asm
; wcl386 first.obj driver.c asm_io.obj
%include "asm_io.inc"
;
; initialized data is put in the .data segment
;
segment .data
;
; These labels refer to strings used for output
;
prompt1 db "Enter a number: ", 0 ; don't forget nul terminator
prompt2 db "Enter another number: ", 0
outmsg1 db "You entered ", 0
outmsg2 db " and ", 0
outmsg3 db ", the sum of these is ", 0
;
; uninitialized data is put in the .bss segment
;
segment .bss
;
; These labels refer to double words used to store the inputs
;
input1 resd 1
input2 resd 1
;
; code is put in the .text segment
;
segment .text
global _asm_main
_asm_main:
enter 0,0 ; setup routine
pusha
mov eax, prompt1 ; print out prompt
call print_string
call read_int ; read integer
mov [input1], eax ; store into input1
mov eax, prompt2 ; print out prompt
call print_string
call read_int ; read integer
mov [input2], eax ; store into input2
mov eax, [input1] ; eax = dword at input1
add eax, [input2] ; eax += dword at input2
mov ebx, eax ; ebx = eax
dump_regs 1 ; dump out register values
dump_mem 2, outmsg1, 1 ; dump out memory
;
; next print out result message as series of steps
;
mov eax, outmsg1
call print_string ; print out first message
mov eax, [input1]
call print_int ; print out input1
mov eax, outmsg2
call print_string ; print out second message
mov eax, [input2]
call print_int ; print out input2
mov eax, outmsg3
call print_string ; print out third message
mov eax, ebx
call print_int ; print out sum (ebx)
call print_nl ; print new-line
popa
mov eax, 0 ; return back to C
leave
ret
驱动器.c：
#include "cdecl.h"
int PRE_CDECL asm_main( void ) POST_CDECL;
int main()
{
int ret_status;
ret_status = asm_main();
return ret_status;
}
现在我使用以下方法编译它：
nasm -f macho first.asm
nasm -f 男子气概 asm_io.asm
gcc first.o asm_io.o driver.c -o first -arch i386
然后运行：./first
分段故障
仅当我使用 asm_io lib 时才会发生这种情况。
谢谢，
丹尼尔·科赫