在过去的两天里,我研究了这个主题,并尝试了多种方法来尝试解决我在程序中遇到的这个问题。该程序假设采用 16 位随机密钥并将其与用户输入的消息进行异或。我的程序目前没有错误,但我遇到了问题。
import string
import random
message = raw_input("Enter your message: ").split(",")
size = 2 # or whatever lenght you want your random string to be
allowed = string.ascii_letters # add any other allowed characters here
randomstring = ''.join([allowed[random.randint(0, len(allowed) - 1)] for x in xrange(size)])
print
print("This is the key used for encryption:")
print randomstring #prints out key used
print
print("APPLYING XOR METHOD TO MESSAGE AND KEY")
print("--------------------------------------")
for i in xrange(0,len(message)-1):
l += [ord(message) ^ ord(randomstring) for message,randomstring in zip(message,randomstring)]
print l
print
#BRUTE FORCE TO FIND OUT RANDOMSTRING
key= []
count =0
while(key!=randomstring):
key = ''.join([allowed[random.randint(0, len(allowed) - 1)] for x in xrange(size)])
count = count + 1
if(key==randomstring):
print ("FOUND KEY USED BY BRUTE FORCE: "+key)
print (count)
break
此代码生成随机密钥并在 for 循环完成后找出相同的密钥。例如我的输出是,
Enter your message: hi
This is the key used for encryption:
ng
APPLYING XOR METHOD TO MESSAGE AND KEY
--------------------------------------
FOUND KEY USED BY BRUTE FORCE: ng
1052
我需要一种将加密的 XOR 消息打印到屏幕上的方法。先感谢您!