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我正在编写一个小型 Rub​​y 算法,该算法仅在以“1”结尾的值上引发上述错误,例如“21”、“31”、“41”。

success = []
(1..9_999_999).each do |num|
  num_s = num.to_s.split("")
    if num_s.inject(0){ |memo, val| memo += (1..val.to_i).inject(&:*) } == num
      success << []
    end
end

奇怪的是,主代码行本身没有错误:

["2", "1"].inject(0){ |memo, val| memo += (1..val.to_i).inject(&:*) } #-> 3 

基于错误,我认为这样做可能有问题:

(1.."1".to_i).inject(&:*) #-> 1

但是没有......我很困惑。

4

1 回答 1

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>> ["1", "0"].inject(0){ |memo, val| memo += (1..val.to_i).inject(&:*) } #-> 3
TypeError: nil can't be coerced into Fixnum
        from (irb):2:in `+'
        from (irb):2:in `block in irb_binding'
        from (irb):2:in `each'
        from (irb):2:in `inject'
        from (irb):2
        from C:/Ruby200-x64/bin/irb:12:in `<main>'

发生上述错误是因为:(1..0).inject(&:*)return nil

>> (1..0).inject(&:*)
=> nil
>> 0 * (1..0).inject(&:*)
TypeError: nil can't be coerced into Fixnum
        from (irb):4:in `*'
        from (irb):4
        from C:/Ruby200-x64/bin/irb:12:in `<main>'
于 2013-10-02T16:26:58.463 回答