我正在尝试json
在我的网站上显示。JSON
应该正确格式化,但它被包装了。
目前是:
{"ids":[{"id":"52","name":"\u0633\u0633\u064a john","sex":"\u0635\u0628\u064a","国籍":"德国人"} ,{"id":"50","name":"\u0645\u062d\u0645\u062f sjajha ha","sex":"\u0630\u0643\u0631","国籍":"\u0628\u062d\ u0631\u0627\u0646\u064a"}],"成功":1}
虽然它应该是这样的:
{
"success": 1,
"product": [
{
"pid": "1",
"name": "iPHone 4S",
"price": "300.00",
"description": "iPhone 4S white",
"created_at": "2012-04-29 01:41:42",
"updated_at": "0000-00-00 00:00:00"
}
]
}
这是我的 php 代码:
<html>
<head>
<title>Send and Rec data to Android Device</title>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/>
</head>
<body>
<?php
/*
* Following code will list all the ids
*/
$db = mysql_connect($dbhost, $dbuser, $dbpass);
mysql_query("SET character_set_results = 'utf8', character_set_client = 'utf8', character_set_connection = 'utf8', character_set_database = 'utf8', character_set_server = 'utf8'", $db);
mysql_set_charset('utf8', $db);
$charset = mysql_client_encoding($db);
// array for JSON response
$response = array();
// include db connect class
// connecting to db
// get all ids from ids table
$result = mysql_query("SELECT * FROM people") or die(mysql_error());
// check for empty result
if (mysql_num_rows($result) > 0) {
// looping through all results
// ids node
$response["ids"] = array();
while ($row = mysql_fetch_array($result)) {
// temp user array
$idd = array();
$idd["id"] = $row["id"];
$idd["name"] = $row["name"];
$idd["sex"] = $row["sex"];
$idd["nationality"] = $row["nationality"];
// push single idd into final response array
array_push($response["ids"], $idd);
}
// success
$response["success"] = 1;
// echoing JSON response
echo json_encode($response);
} else {
// no ids found
$response["success"] = 0;
$response["message"] = "No ids found";
// echo no users JSON
echo json_encode($response);
}
?>
</body>
</html>