sql - Ms Sql Split and Convert

Question

I have ID as a varchar. I need to split as Comma after that i need to convert list to int32. I added example like below.

DECLARE @List varchar(255)

SET @List = '1, 2, 3, 4, 5, 6'

print @List

Answer 1

您可以尝试以下方法：

DECLARE @List varchar(255) = '1, 2, 23, 4, 5, 6'

DECLARE @X XML
SELECT @X  = '<myxml><nodes><n>' + 
              REPLACE(@List,',','</n></nodes><nodes><n>') + 
             '</n></nodes></myxml>'

--SELECT @X

SELECT LTRIM(C.value('n[1]','VARCHAR(50)')) AS item1
FROM @X.nodes('/myxml/nodes') Cols (C)

小提琴演示

结果：

| ITEM1 |
--------|--
|     1 |
|     2 |
|    23 |
|     4 |
|     5 |
|     6 |

注意：如果根据您的样本数据 ( ) 在数字之间有空格，则可以在转换为 INT 之前2 3使用函数将其删除。IsNumeric()函数也可能有用（有关详细信息，请阅读 isNumeric() 函数的注释部分）。Replace()

Answer 2

我已经从pswg 的答案中改编了一个脚本，该脚本将一个字符串拆分为 int 的内存表：

CREATE FUNCTION [dbo].[SplitToIntList] 
    ( @string nvarchar(4000)
    , @delim nvarchar(100) )
RETURNS
    @result TABLE ([Value] int NULL)
AS
BEGIN
    DECLARE @str nvarchar(4000)
          , @pos int 
          , @prv int = 1

    SELECT @pos = CHARINDEX(@delim, @string)
    WHILE @pos > 0
    BEGIN
        SELECT @str = SUBSTRING(@string, @prv, @pos - @prv)
        INSERT INTO @result SELECT CAST(@str AS INT)

        SELECT @prv = @pos + LEN(@delim)
             , @pos = CHARINDEX(@delim, @string, @pos + 1)
    END

    INSERT INTO @result SELECT CAST(SUBSTRING(@string, @prv, 4000) AS INT)
    RETURN
END

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