2

我有带有国家名称的源数组和带有产品的其他数组。两个数组的索引相等。

array1:{China, China, Korea, USA, USA},

array2:{Lenovo, Asus, Samsung, Apple, Blackberry},

result : array : {{China, {Lenovo, Asus}}, {Korea, {Samsung}} ... }

但我无法正确分组数组。我总能得到结果

{{China, {Lenovo}},{China, {Asus}} ... }.

我的代码是：

for (i = 0; i < XArray.length; i++) {
    var pointsArray = [];

    for (j = 0; j < XArray.length; j++) {

        if (XArray[i] == XArray[j]) {
            pointsArray.push([parseFloat(YArray[i]), parseFloat(ZArray[i])]);
        }
    }

    dataSource.push({
        name: i,
        data: pointsArray.slice()
    });
    pointsArray.length = 0;
}
4

2 回答 2

4

我认为您应该使用一个对象按国家/地区对制造商进行分组。像这样：

var conutries,
    manufacturers,
    i,
    len,
    country,
    manufacturerByCountry;
countries = ['China', 'China', 'Korea', 'USA', 'USA'];
manufacturers = ['Lenovo', 'Asus', 'Samsung', 'Apple', 'Blackberry'];
len = countries.length;
manufacturerByCountry = {};
// expected result:
// array : {'China': ['Lenovo', 'Asus'], 'Korea': ['Samsung'] ... }

for(i = 0; i < len; i++) {
    country = countries[i];
    if(!manufacturerByCountry[country]) {
        manufacturerByCountry[country] = [];
    }
    manufacturerByCountry[country].push(manufacturers[i]);
}

console.log(manufacturerByCountry);

演示

如果您仍然想获得您所描述的结果，那么您可以使用这样的解决方案：

var conutries,
    manufacturers,
    i,
    len,
    country,
    manufacturerByCountry,
    countryIndex,
    index;
countries = ['China', 'China', 'Korea', 'USA', 'USA'];
manufacturers = ['Lenovo', 'Asus', 'Samsung', 'Apple', 'Blackberry'];
len = countries.length,
manufacturerByCountry = [],
countryIndex = {};
// expected result:
// array : [[China, [Lenovo, Asus]], [Korea, [Samsung]] ... ]

for(i = 0; i < len; i++) {
    country = countries[i];
    if(countryIndex[country] === undefined) {
        index = manufacturerByCountry.push([country, []]) - 1;
        countryIndex[country] = index;
    } else {
        index = countryIndex[country];
    }
    manufacturerByCountry[index][1].push(manufacturers[i]);
}

console.log(manufacturerByCountry);

演示

于 2013-10-02T06:04:35.127 回答
0

不太确定语法，但我认为您正在尝试这样做：

var array1 = ['China', 'China', 'Korea', 'USA', 'USA'];
var array2 = ['Lenovo', 'Asus', 'Samsung', 'Apple', 'Blackberry'];
var result = [];
var name, names = {};
var nameCount = 0;
var obj;

for (var i=0, iLen=array1.length; i<iLen; i++) {
  name = array1[i];

  // If haven't found name already, setup structure
  // so value can be added after the block
  if (!(name in names)) {

    // Add name to the list of names and remember its index
    names[name] = nameCount;

    // Create a new object
    obj = {};

    // Give it a property with value of name and assign an array
    obj[name] = [];

    // Add it to results
    result.push(obj);

    // Increment index for next time
    ++nameCount;
  }

  // Add member of array2 to name object's array
  result[names[name]][name].push(array2[i]);
}

它创建了一个对象数组，例如：

[
  {China: ['Lenovo', 'Asus']},
  {Korea: ['Samsung']},
  {USA:   ['Apple', 'Blackberry']}
]
于 2013-10-02T06:24:53.927 回答